C - Football

标签：desc   nbsp   another   current   imp   after   code   flag   each   

Problem description

Petya loves football very much. One day, as he was watching a football match, he was writing the players‘ current positions on a piece of paper. To simplify the situation he depicted it as a string consisting of zeroes and ones. A zero corresponds to players of one team; a one corresponds to players of another team. If there are at least 7 players of some team standing one after another, then the situation is considered dangerous. For example, the situation 00100110111111101 is dangerous and 11110111011101 is not. You are given the current situation. Determine whether it is dangerous or not.

Input

The first input line contains a non-empty string consisting of characters "0" and "1", which represents players. The length of the string does not exceed 100characters. There‘s at least one player from each team present on the field.

Output

Print "YES" if the situation is dangerous. Otherwise, print "NO".

Examples

001001

NO

1000000001

YES
解题思路：题目很简单(水)，简单处理字符串，如果有连续相同的数字不小于7个，则输出"YES"，否则输出"NO"。
AC代码：

 1 #include <bits/stdc++.h>
 2 using namespace std;
 3 int main()
 4 {
 5     char a[105];int cnt=0,i=0;bool flag=false;
 6     cin>>a;
 7     while(a[i]!=‘\0‘){
 8         if(a[i]==‘1‘){while(a[i]==‘1‘){cnt++;i++;}}
 9         else{while(a[i]==‘0‘){cnt++;i++;}}
10         if(cnt>=7){flag=true;break;}
11         cnt=0;
12     }
13     if(flag)cout<<"YES"<<endl;
14     else cout<<"NO"<<endl;
15     return 0;
16 }

C - Football

标签：desc   nbsp   another   current   imp   after   code   flag   each   

原文地址：https://www.cnblogs.com/acgoto/p/9105368.html