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hdu 5053 the Sum of Cube---2014acm上海赛区网络赛

时间:2014-09-27 22:16:30      阅读:191      评论:0      收藏:0      [点我收藏+]

标签:2014acm上海赛区网络赛   水题   数学   算法   

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=5053


the Sum of Cube

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 140    Accepted Submission(s): 80


Problem Description
A range is given, the begin and the end are both integers. You should sum the cube of all the integers in the range.
 

Input
The first line of the input is T(1 <= T <= 1000), which stands for the number of test cases you need to solve.
Each case of input is a pair of integer A,B(0 < A <= B <= 10000),representing the range[A,B].
 

Output
For each test case, print a line “Case #t: ”(without quotes, t means the index of the test case) at the beginning. Then output the answer – sum the cube of all the integers in the range.
 

Sample Input
2 1 3 2 5
 

Sample Output
Case #1: 36 Case #2: 224
 

Source
 

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一道送分题,不过要小心中间过程溢出。。。


//#pragma comment(linker, "/STACK:36777216")
#include <functional>
#include <algorithm>
#include <iostream>
#include <fstream>
#include <sstream>
#include <iomanip>
#include <numeric>
#include <cstring>
#include <climits>
#include <cassert>
#include <complex>
#include <cstdio>
#include <string>
#include <vector>
#include <bitset>
#include <queue>
#include <stack>
#include <cmath>
#include <ctime>
#include <list>
#include <set>
#include <map>
using namespace std;
int main(){
    #ifdef ONLINE_JUDGE
    #else
        freopen("in.txt","r",stdin);
    #endif
    int T,kase=0;
    scanf("%d",&T);
    while(T--){
        printf("Case #%d: ",++kase);
        long long A,B;
        scanf("%I64d%I64d",&A,&B);
        long long sum=0;
        long long sum1=(A-1)*(A)/2;
        sum1=sum1*sum1;
        long long sum2=(B)*(B+1)/2;
        sum2=sum2*sum2;
        cout<<sum2-sum1<<endl;
    }
    return 0;
}





hdu 5053 the Sum of Cube---2014acm上海赛区网络赛

标签:2014acm上海赛区网络赛   水题   数学   算法   

原文地址:http://blog.csdn.net/asdfghjkl1993/article/details/39615445

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