标签:release bsp 一个 count CQ spl tar %s lease
from threading import Thread,RLock import time mutexA=mutexB=RLock()
#一个线程拿到锁,counter加1,该线程内又碰到加锁的情况,则counter继续加1,
#这期间所有其他线程都只能等待,等待该线程释放所有锁,即counter递减到0为止 class MyThread(Thread): def run(self): self.func1() self.func2() def func1(self): mutexA.acquire() print(‘\033[41m%s 拿到A锁\033[0m‘ %self.name) mutexB.acquire() print(‘\033[42m%s 拿到B锁\033[0m‘ %self.name) mutexB.release() mutexA.release() def func2(self): mutexB.acquire() print(‘\033[43m%s 拿到B锁\033[0m‘ %self.name) time.sleep(2) mutexA.acquire() print(‘\033[44m%s 拿到A锁\033[0m‘ %self.name) mutexA.release() mutexB.release() if __name__ == ‘__main__‘: for i in range(10): t=MyThread() t.start()
标签:release bsp 一个 count CQ spl tar %s lease
原文地址:https://www.cnblogs.com/yelublue/p/9123246.html