标签:note lex tput ati array def red val nat
Given a non-empty array of integers, return the third maximum number in this array. If it does not exist, return the maximum number. The time complexity must be in O(n).
Example 1:
Input: [3, 2, 1] Output: 1 Explanation: The third maximum is 1.
Example 2:
Input: [1, 2] Output: 2 Explanation: The third maximum does not exist, so the maximum (2) is returned instead.
Example 3:
Input: [2, 2, 3, 1] Output: 1 Explanation: Note that the third maximum here means the third maximum distinct number. Both numbers with value 2 are both considered as second maximum.
python实现起来很简单,先set去重,然后list反向排序
class Solution(object): def thirdMax(self, nums): """ :type nums: List[int] :rtype: int """ l = list(set(nums)) l.sort(reverse=True) if len(l) < 3: return l[0] return l[2]
标签:note lex tput ati array def red val nat
原文地址:https://www.cnblogs.com/jeroen/p/9152608.html