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A - I Wanna Be the Guy

时间:2018-06-09 13:57:17      阅读:196      评论:0      收藏:0      [点我收藏+]

标签:integer   using   dice   not   format   als   c++   cte   sed   

Problem description

There is a game called "I Wanna Be the Guy", consisting of n levels. Little X and his friend Little Y are addicted to the game. Each of them wants to pass the whole game.

Little X can pass only p levels of the game. And Little Y can pass only q levels of the game. You are given the indices of levels Little X can pass and the indices of levels Little Y can pass. Will Little X and Little Y pass the whole game, if they cooperate each other?

Input

The first line contains a single integer n (1?≤??n?≤?100).

The next line contains an integer p (0?≤?p?≤?n) at first, then follows p distinct integers a1,?a2,?...,?ap (1?≤?ai?≤?n). These integers denote the indices of levels Little X can pass. The next line contains the levels Little Y can pass in the same format. It‘s assumed that levels are numbered from 1 to n.

Output

If they can pass all the levels, print "I become the guy.". If it‘s impossible, print "Oh, my keyboard!" (without the quotes).

Examples

Input
4
3 1 2 3
2 2 4
Output
I become the guy.
Input
4
3 1 2 3
2 2 3
Output
Oh, my keyboard!

Note

In the first sample, Little X can pass levels [1 2 3], and Little Y can pass level [2 4], so they can pass all the levels both.

In the second sample, no one can pass level 4.

解题思路:标记一下1~n出现的数字,如果都出现了,则输出"I become the guy.",否则输出"Oh, my keyboard!",水过!

AC代码:

 1 #include<bits/stdc++.h>
 2 using namespace std;
 3 int main(){
 4     int n,p,q,x;bool flag=false,used[105];
 5     memset(used,false,sizeof(used));
 6     cin>>n>>p;
 7     for(int i=1;i<=p;++i){cin>>x;used[x]=true;}
 8     cin>>q;
 9     for(int i=1;i<=q;++i){cin>>x;used[x]=true;}
10     for(int i=1;i<=n;++i)
11         if(!used[i]){flag=true;break;}
12     if(flag)cout<<"Oh, my keyboard!"<<endl;
13     else cout<<"I become the guy."<<endl;
14     return 0;
15 }

 

A - I Wanna Be the Guy

标签:integer   using   dice   not   format   als   c++   cte   sed   

原文地址:https://www.cnblogs.com/acgoto/p/9159193.html

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