标签:sea .com tor max else color class i++ 距离
题目链接:https://leetcode.com/problems/maximize-distance-to-closest-person/description/
思路:pre[i]存放i之前离最近的1的距离。post记录之后的。 res = max(min(pre[i],[post[i]))
注意点:初始nst需要设计极大或极小值。
1 int maxDistToClosest(vector<int>& seats) { 2 vector<int> pre,post; 3 int n = seats.size(); 4 pre.assign(n,0); 5 post.assign(n,0); 6 int nst = -200000; 7 for(int i = 0; i < n; i++){ 8 if(seats[i] == 1){ 9 nst = i; 10 }else{ 11 pre[i] = i - nst; 12 } 13 } 14 nst = 200000; 15 for(int i = n - 1; i >= 0; i--){ 16 if(seats[i]==1){ 17 nst = i; 18 }else{ 19 post[i] = nst - i; 20 } 21 } 22 int res = 0; 23 for(int i = 0; i<n; i++ ){ 24 int temp = min(pre[i],post[i]); 25 res = max(res,temp); 26 } 27 return res; 28 }
849. Maximize Distance to Closest Person ——weekly contest 87
标签:sea .com tor max else color class i++ 距离
原文地址:https://www.cnblogs.com/jinjin-2018/p/9165164.html