码迷,mamicode.com
首页 > 其他好文 > 详细

A - Fox And Snake

时间:2018-06-17 11:04:31      阅读:143      评论:0      收藏:0      [点我收藏+]

标签:tab   empty   wing   names   pat   XA   NPU   his   include   

Problem description

Fox Ciel starts to learn programming. The first task is drawing a fox! However, that turns out to be too hard for a beginner, so she decides to draw a snake instead.

A snake is a pattern on a n by m table. Denote c-th cell of r-th row as (r,?c). The tail of the snake is located at (1,?1), then it‘s body extends to (1,?m), then goes down 2 rows to (3,?m), then goes left to (3,?1) and so on.

Your task is to draw this snake for Fox Ciel: the empty cells should be represented as dot characters (‘.‘) and the snake cells should be filled with number signs (‘#‘).

Consider sample tests in order to understand the snake pattern.

Input

The only line contains two integers: n and m (3?≤?n,?m?≤?50).

n is an odd number.

Output

Output n lines. Each line should contain a string consisting of m characters. Do not output spaces.

Examples

Input
3 3
Output
###
..#
###
Input
3 4
Output
####
...#
####
Input
5 3
Output
###
..#
###
#..
###
Input
9 9
Output
#########
........#
#########
#........
#########
........#
#########
#........
#########
解题思路:按规律输出,当i为奇数时,输出的一行全部为‘#‘;当i为偶数时,用flag做开关,交换输出两种格式,水过!
AC代码:
 1 #include<bits/stdc++.h>
 2 using namespace std;
 3 #define FOR(a,b,c) for(int i=a;i<=b;++i)printf("%c",c)
 4 int n,m;bool flag;
 5 int main(){
 6     cin>>n>>m;flag=false;
 7     for(int i=1;i<=n;++i){
 8         if(i%2)FOR(1,m,#);
 9         else{
10             if(!flag){FOR(1,m-1,.);cout<<#;flag=true;}
11             else{cout<<#;FOR(2,m,.);flag=false;}
12         }
13         cout<<endl;
14     }
15     return 0;
16 }

 

A - Fox And Snake

标签:tab   empty   wing   names   pat   XA   NPU   his   include   

原文地址:https://www.cnblogs.com/acgoto/p/9191968.html

(0)
(0)
   
举报
评论 一句话评论(0
登录后才能评论!
© 2014 mamicode.com 版权所有  联系我们:gaon5@hotmail.com
迷上了代码!