标签：each cep return TE number head lis lse except
[TOC]
Given a non-empty array of digits representing a non-negative integer, plus one to the integer.
The digits are stored such that the most significant digit is at the head of the list, and each element in the array contain a single digit.
You may assume the integer does not contain any leading zero, except the number 0 itself.
Example 1:
Input: [1,2,3]
Output: [1,2,4]
Explanation: The array represents the integer 123.Example 2:
Input: [4,3,2,1]
Output: [4,3,2,2]
Explanation: The array represents the integer 4321.class Solution {
public int[] plusOne(int[] digits) {
int n = digits.length;
for (int i=n-1; i>=0; i--) {
if (digits[i] < 9) {
digits[i]++;
return digits;
}
digits[i] = 0;
}
int[] newNum = new int[n+1];
newNum[0] = 1;
return newNum;
}
}Runtime:?0 ms
class Solution:
def plusOne(self, digits):
"""
:type digits: List[int]
:rtype: List[int]
"""
i = len(digits) - 1
while digits[i] == 9 and i>=0:
digits[i] = 0
i -= 1
if i < 0:
return [1] + digits
else:
digits[i] += 1
return digitsRuntime:?44 ms
class Solution:
def plusOne(self, digits):
"""
:type digits: List[int]
:rtype: List[int]
"""
num = 0
for i in range(len(digits)):
num += digits[i] * pow(10, len(digits)-1-i)
return [int(n) for n in str(num+1)]Runtime:?40 ms
class Solution:
def plusOne(self, digits):
"""
:type digits: List[int]
:rtype: List[int]
"""
return [int(n) for n in str(int(''.join(map(str, digits))) + 1)]Runtime:?40 ms
标签：each cep return TE number head lis lse except
原文地址：https://www.cnblogs.com/xugenpeng/p/9192483.html
