标签:== The har eve dad val iii app inpu
问题描述:
Roman numerals are represented by seven different symbols: I
, V
, X
, L
, C
, D
and M
.
Symbol Value I 1 V 5 X 10 L 50 C 100 D 500 M 1000
For example, two is written as II
in Roman numeral, just two one‘s added together. Twelve is written as, XII
, which is simply X
+ II
. The number twenty seven is written as XXVII
, which is XX
+ V
+ II
.
Roman numerals are usually written largest to smallest from left to right. However, the numeral for four is not IIII
. Instead, the number four is written as IV
. Because the one is before the five we subtract it making four. The same principle applies to the number nine, which is written as IX
. There are six instances where subtraction is used:
I
can be placed before V
(5) and X
(10) to make 4 and 9. X
can be placed before L
(50) and C
(100) to make 40 and 90. C
can be placed before D
(500) and M
(1000) to make 400 and 900.Given a roman numeral, convert it to an integer. Input is guaranteed to be within the range from 1 to 3999.
Example 1:
Input: "III" Output: 3
Example 2:
Input: "IV" Output: 4
Example 3:
Input: "IX" Output: 9
Example 4:
Input: "LVIII" Output: 58 Explanation: C = 100, L = 50, XXX = 30 and III = 3.
Example 5:
Input: "MCMXCIV" Output: 1994 Explanation: M = 1000, CM = 900, XC = 90 and IV = 4.
解题思路:
不难看出:
1. 当当前数字比其右边数字小的时候,则减去当前数字。
2. 当当前数字比其右边数字大或等于右边数字时,则加上当前数字。
与12. Integer to Roman可构成一个系列
代码:
class Solution { public: int romanToInt(string s) { if(s.size() == 0) return 0; unordered_map<char, int> charMap; charMap[‘I‘] = 1; charMap[‘V‘] = 5; charMap[‘X‘] = 10; charMap[‘L‘] = 50; charMap[‘C‘] = 100; charMap[‘D‘] = 500; charMap[‘M‘] = 1000; int n = s.size()-1; int ret = charMap[s[n]]; for(int i = n-1; i > -1; i--){ if(charMap[s[i+1]] > charMap[s[i]]) ret -= charMap[s[i]]; else ret += charMap[s[i]]; } return ret; } };
标签:== The har eve dad val iii app inpu
原文地址:https://www.cnblogs.com/yaoyudadudu/p/9216101.html