标签:AC style read TE cli iostream play CM 序列
题意:
给定一个序列,以最小代价将其变成单调不增或单调不减序列,代价为Σabs(i变化后-i变化前),序列长度<=2000,单个数字<=1e9
输入:(第一行表示序列长度,之后一行一个表示序列第i的大小)
7
1
3
2
4
5
3
9
输出:(代价)1 #include<set> 2 #include<map> 3 #include<queue> 4 #include<stack> 5 #include<cmath> 6 #include<cstdio> 7 #include<cstring> 8 #include<iostream> 9 #include<algorithm> 10 #define RG register ll 11 #define rep(i,a,b) for(RG i=a;i<=b;++i) 12 #define per(i,a,b) for(RG i=a;i>=b;--i) 13 #define ll long long 14 #define inf (1<<30) 15 #define maxn 2005 16 using namespace std; 17 ll n; 18 ll a[maxn],b[maxn],dp[maxn][maxn]; 19 inline ll read() 20 { 21 ll x=0,f=1;char c=getchar(); 22 while(c<‘0‘||c>‘9‘){if(c==‘-‘)f=-1;c=getchar();} 23 while(c>=‘0‘&&c<=‘9‘){x=x*10+c-‘0‘;c=getchar();} 24 return x*f; 25 } 26 27 void work() 28 { 29 rep(i,1,n) 30 { 31 ll mn=inf; 32 rep(j,1,n) 33 { 34 mn=min(mn,dp[i-1][j]); 35 dp[i][j]=(a[i]-b[j]>=0?a[i]-b[j]:b[j]-a[i])+mn; 36 } 37 } 38 ll ans=inf; 39 rep(i,1,n) ans=min(ans,dp[n][i]); 40 cout<<ans; 41 } 42 43 int main() 44 { 45 n=read(); 46 rep(i,1,n) a[i]=b[i]=read(); 47 sort(b+1,b+1+n); 48 work(); 49 return 0; 50 }
Making the Grade [POJ3666] [DP]
标签:AC style read TE cli iostream play CM 序列
原文地址:https://www.cnblogs.com/ibilllee/p/9220613.html