标签：under main ret ati space problem P20 i++ lan
题解做法：没有用把阶乘算出来就得出了答案( ⊙ o ⊙ )啊！神奇呢！
#include<iostream>
#include<cstdio>
using namespace std;
int a[10001],n;
int main()
{
scanf("%d",&n);
for(int i=2;i<=n;i++)
{
int w=i;
for(int j=2;j<=i;j++)
while(w%j==0)
{
a[j]++;
w=w/j;
}
}
for(int i=1;i<=10000;i++)
if(a[i]!=0)
cout<<i<<" "<<a[i]<<endl;
return 0;
}
标签：under main ret ati space problem P20 i++ lan
原文地址：https://www.cnblogs.com/xrj1229/p/9235942.html
