PAT 乙级 1047 编程团体赛

标签：string   max   else   using   xid   ima   pair   inner   image   

输入样例：
6
3-10 99
11-5 87
102-1 0
102-3 100
11-9 89
3-2 61
输出样例：
11 176

思路是建立一张表，以队伍编号为关键字，以队伍总成绩为关键字对应的值。统计时直接查表。

#include <iostream>
#include <stdio.h>
#include <string.h>
#include <string>
#include <map>
#include <queue>
#include <stack>
#include <algorithm>

using namespace std;

struct TeamMember
{
    int idOfTeam,idOfMember,score;
    friend istream& operator>>(istream& str,TeamMember& m)
    {
        cin>>m.idOfTeam;
        getchar();
        cin>>m.idOfMember;
        getchar();
        cin>>m.score;
    }
};


void countWinner(TeamMember* p,int n);

int main()
{
    int n;
    cin>>n;
    TeamMember* p=new TeamMember[n];
    for(int i=0;i<n;i++)
        cin>>p[i];
    countWinner(p,n);
    delete p;
    return 0;
}

void countWinner(TeamMember* p,int n)
{
    map<int,int> m;
    map<int,int>::iterator itor;
    for(int i=0;i<n;i++)
    {
        itor=m.find(p[i].idOfTeam);
        if(itor==m.end())
            m.insert(pair<int,int>(p[i].idOfTeam,p[i].score));
        else
            itor->second+=p[i].score;
    }
    int maxIdOfTeam=0,maxScore=0;
    for(itor=m.begin() ;itor!=m.end() ;itor++)
    {
        if(itor->second>maxScore)
        {
            maxIdOfTeam=itor->first;
            maxScore=itor->second;
        }
    }
    cout<<maxIdOfTeam<<" "<<maxScore;
}

PAT 乙级 1047 编程团体赛

标签：string   max   else   using   xid   ima   pair   inner   image   

原文地址：https://www.cnblogs.com/FDProcess/p/9245758.html