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HDU 1012 u Calculate e(简单阶乘计算)

时间:2018-07-15 13:46:53      阅读:141      评论:0      收藏:0      [点我收藏+]

标签:value   阶乘   similar   ble   using   i++   arc   ace   return   

传送门:

http://acm.hdu.edu.cn/showproblem.php?pid=1012

u Calculate e

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 52607    Accepted Submission(s): 24106


Problem Description
A simple mathematical formula for e is

技术分享图片

where n is allowed to go to infinity. This can actually yield very accurate approximations of e using relatively small values of n.
 

 

Output
Output the approximations of e generated by the above formula for the values of n from 0 to 9. The beginning of your output should appear similar to that shown below.
 

 

Sample Output
n e
- -----------
0 1
1 2
2 2.5
3 2.666666667
4 2.708333333
 

 

Source
 分析:
没有什么好说的
水题
code:
#include<bits/stdc++.h>
using namespace std;
typedef long long LL;
int f(int x)
{
    if(x==0)
        return 1;
    if(x==1)
        return 1;
    LL sum=1;
    for(int i=1;i<=x;i++)
    {
        sum*=i;
    }
    return sum;
}
int main()
{
    printf("n e\n");
    printf("- -----------\n");
    printf("0 1\n1 2\n2 2.5\n");
    for(int i=3;i<=9;i++)
    {
        double result=0;
        for(int j=0;j<=i;j++)
        {
            result+=(1.0/(f(j)*1.0));
        }
        printf("%d %0.9lf\n",i,result);
    }
    return 0;
}

 

HDU 1012 u Calculate e(简单阶乘计算)

标签:value   阶乘   similar   ble   using   i++   arc   ace   return   

原文地址:https://www.cnblogs.com/yinbiao/p/9313265.html

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