E - Cheap Kangaroo

标签：ret   type   heap   first   sep   feed   pac   bit   tis   

Description

There are N kangaroos going out to eat at an Indian restaurant. The i^th kangaroo wants to eat exactly x_i food. The kangaroos all want to order the same size of plates, but each one can order more than one plate for themselves if they need to. If the kangaroo orders more than he needs, he can simply hide the leftovers in his pouch.

At this Indian restaurant, the cost of the plate is the same as its size. Since Karl the Kangaroo is paying and is low on money, he wants to know what is the minimum cost to feed all N kangaroos and what is the largest possible size of the plates that satisfies this minimum cost?

Input

The first line of input is T – the number of test cases.

The first line of each test case is an integer N (1?≤?N?≤?10⁵).

The second line contains N space-separated integers x_i (1?≤?x_i?≤?10⁹).

Output

For each test case, output a line containing two space-separated integers – the minimum cost and the maximum plate size that corresponds to when the total cost is minimized.

Example

2
1
5
2
4 2

5 5
6 2
解题思路：题目的意思就是求n只袋鼠需要的食物总量和所有的食物的数量（盘子的大小）的最大公约数，水过！
AC代码：

 1 #include<bits/stdc++.h>
 2 using namespace std;
 3 typedef long long LL;
 4 int gcd(int a,int b){
 5     return b?gcd(b,a%b):a;
 6 }
 7 int main(){
 8     int t,n,x,ans;LL sum;
 9     scanf("%d",&t);
10     while(t--){
11         scanf("%d",&n);
12         scanf("%d",&x);
13         ans=sum=x;
14         for(int i=1;i<n;++i){
15             scanf("%d",&x);
16             sum+=x;
17             ans=gcd(ans,x);
18         }
19         printf("%lld %d\n",sum,ans);
20     }
21     return 0;
22 }

E - Cheap Kangaroo

标签：ret   type   heap   first   sep   feed   pac   bit   tis   

原文地址：https://www.cnblogs.com/acgoto/p/9315857.html