区间DP POJ1160村庄邮局问题

#include <iostream>
#include <cstdio>
#include <string.h>
#define inf (1e8 + 9e7)
using namespace std;
const int maxn = 1e3 + 1e2;
int dp[maxn][maxn];
int sum[maxn][maxn];
int pos[maxn];
void init()
{
    memset(sum,0,sizeof(sum));
}
int main()
{
    int n,pn;
    while(~scanf("%d%d",&n,&pn))
    {
        init();
        for(int i = 1;i <= n;i++)
            scanf("%d",&pos[i]);

        for(int i = 1;i <= n;i++)
        {
            for(int j = i+1;j <= n;j++)
            {
                sum[i][j] = sum[i][j-1] + pos[j] - pos[(i + j)/2];
            }
            dp[i][i] = 0;
        }

        for(int i = 1;i <= n;i++)
        {
            dp[i][1] = sum[1][i];
        }

        for(int j = 2;j <= pn;j++)//建造一个的情况已经铺垫好了
            for(int i = j+1;i <= n;i++)//村庄首先必须保证得比
            {
                //接下来我要做的是遍历k来找到到底几个村庄放j-1个最优
                dp[i][j] = inf;
                for(int k = j - 1;k < i;k++)
                {
                    dp[i][j] = min(dp[i][j],dp[k][j-1] + sum[k+1][i]);
                }
            }
        printf("%d\n",dp[n][pn]);
    }
    return 0;
}