AtCoder Beginner Contest 103

Problem Statement

You have three tasks, all of which need to be completed.

First, you can complete any one task at cost $00$.

Then, just after completing the $\mathrm{ii}$-th task, you can complete the $\mathrm{jj}$-th task at cost $|Aj-Ai||Aj-Ai|$.

Here, $|x||x|$ denotes the absolute value of $\mathrm{xx}$.

Find the minimum total cost required to complete all the task.

Constraints

• All values in input are integers.
• $\mathrm{1\le A1,A2,A3\le 1001\le A1,A2,A3\le 100}$

Sample Input 1 Copy

1 6 3

Sample Output 1 Copy

5

When the tasks are completed in the following order, the total cost will be $55$, which is the minimum:

• Complete the first task at cost $00$.
• Complete the third task at cost $22$.
• Complete the second task at cost $33$.

Sample Input 2 Copy

11 5 5

Sample Output 2 Copy

6

Sample Input 3 Copy

100 100 100

Sample Output 3 Copy

0

import java.util.Arrays;
import java.util.Scanner;
import static java.lang.Math.*;
public class Main {
    
    public static void main(String[] args) {
        Scanner in = new Scanner(System.in);
        int [] a = new int[3];
        for(int i = 0;i < 3;i ++) {
            a[i] = in.nextInt();
        }
        Arrays.sort(a);
        System.out.println(a[2] - a[0]);
    }
}

 B - String Rotation

Time Limit: 2 sec / Memory Limit: 1024 MB

$\mathrm{SS}$
$\mathrm{TT}$

kyoto
tokyo

Yes

abc
arc

No

aaaaaaaaaaaaaaab
aaaaaaaaaaaaaaab

Yes

import java.util.Arrays;
import java.util.Scanner;
import static java.lang.Math.*;
public class Main {
    static boolean check(String a,String b) {
        if(a.length() != b.length())return false;
        for(int i = 0;i < a.length();i ++) {
            if(a.charAt(i) == b.charAt(0) && (a.substring(i, a.length()) + a.substring(0, i)).equals(b)) {
                return true;
            }
        }
        return false;
    }
    public static void main(String[] args) {
        Scanner in = new Scanner(System.in);
        String a = in.nextLine();
        String b = in.nextLine();
        System.out.println(check(a,b) ? "Yes" : "No");
    }
}