标签：example har eating ring longest not char erase The
Given a string, find the length of the longest substring without repeating characters.
Examples:
Given "abcabcbb", the answer is "abc", which the length is 3.
Given "bbbbb", the answer is "b", with the length of 1.
Given "pwwkew", the answer is "wke", with the length of 3. Note that the answer must be a substring, "pwke" is a subsequence and not a substring.
1 class Solution { 2 public: 3 int lengthOfLongestSubstring(string s) { 4 int l = s.length(); 5 map<char, int> m; 6 int innerL = 0; 7 int maxL = 0; 8 for(int i=0; i<l; i++) { 9 map<char, int>::iterator it = m.find(s[i]); 10 if(it != m.end()) { 11 if(maxL < innerL) { 12 maxL = innerL; 13 } 14 i = i - innerL + it->second - 1; 15 innerL = 0; 16 m.erase(m.begin(), m.end()); 17 } 18 else { 19 innerL += 1; 20 m[s[i]] = innerL; 21 } 22 } 23 return (innerL < maxL) ? maxL : innerL; 24 } 25 };
LeetCode - 3.Longest Substring Without Repeating Characters(388ms)
标签：example har eating ring longest not char erase The
原文地址：https://www.cnblogs.com/zlian2016/p/9380088.html
