标签：++ scan pair should bsp color cst pre 输出
Calculate a + b and output the sum in standard format -- that is, the digits must be separated into groups of three by commas (unless there are less than four digits).
Input
Each input file contains one test case. Each case contains a pair of integers a and b where -1000000 <= a, b <= 1000000. The numbers are separated by a space.
Output
For each test case, you should output the sum of a and b in one line. The sum must be written in the standard format.
Sample Input
-1000000 9
Sample Output
-999,991//先求和再将和存储到数组中，倒叙三位一组输出 #include<cstdio> int num[10]; int main(){ int a,b; scanf("%d%d",&a,&b); int sum = a + b; if(sum < 0){ printf("-"); sum = -sum; } int len = 0; if(sum == 0) num[len++] = 0; //可以用do while（）循环就不用对len=0进行特殊处理 while(sum){ num[len++] = sum % 10; sum /= 10; } for(int i = len - 1; i >= 0; i--){ printf("%d",num[i]); if(i > 0 && i % 3 == 0) printf(","); } return 0; }
//printf输出格式中，%3d输出三位整数，位数不足高位补空格 %03位数不足补0 #include<cstdio> int num[10]; int main(){ int a,b; scanf("%d%d",&a,&b); int sum = a + b; if(sum < 0){ printf("-"); sum = -sum; } if(sum >= 1000000) printf("%d,%03d,%03d",sum/1000000,sum%1000000/1000,sum%1000); //第二个数要mod1000000 且等号不能少 else if(sum > 1000) printf("%d,%03d",sum/1000,sum%1000); //1000通过 else { printf("%d",sum); } return 0; }
标签：++ scan pair should bsp color cst pre 输出
原文地址：https://www.cnblogs.com/wanghao-boke/p/9384611.html
