标签:res oms for msu %s code int sum import
import time def comsumer(): need = input("请问需要多少包子:") return need def producer(n): res = [] for i in range(1,n+1): time.sleep(0.2) res.append(‘包子%s‘ %i) return res while True: n = int(comsumer()) m = producer(n) print(m,‘\n这是您的%s个包子,请收好,欢迎下次光临‘ %n)
代码结果如下:
请问需要多少包子:10
[‘包子1‘, ‘包子2‘, ‘包子3‘, ‘包子4‘, ‘包子5‘, ‘包子6‘, ‘包子7‘, ‘包子8‘, ‘包子9‘, ‘包子10‘]
这是您的10个包子,请收好,欢迎下次光临
请问需要多少包子:15
[‘包子1‘, ‘包子2‘, ‘包子3‘, ‘包子4‘, ‘包子5‘, ‘包子6‘, ‘包子7‘, ‘包子8‘, ‘包子9‘, ‘包子10‘, ‘包子11‘, ‘包子12‘, ‘包子13‘, ‘包子14‘, ‘包子15‘]
这是您的15个包子,请收好,欢迎下次光临
请问需要多少包子:
import time def comsumer(): while True: need = input() print("我需要%s个包子" %need) yield need baozi = yield print("谢谢您的%s个包子!" %baozi) producer() def producer(): print("请问您需要多少包子?") a = comsumer() xuqiu = a.__next__() a.__next__() time.sleep(int(xuqiu)/10) res = ["包子%s" %i for i in range(1,int(xuqiu)+1)] print(res,"\n这是您的%s个包子,请收好,欢迎下次光临" %xuqiu) a.send(xuqiu) producer()
代码结果如下:
请问您需要多少包子?
10
我需要10个包子
[‘包子1‘, ‘包子2‘, ‘包子3‘, ‘包子4‘, ‘包子5‘, ‘包子6‘, ‘包子7‘, ‘包子8‘, ‘包子9‘, ‘包子10‘]
这是您的10个包子,请收好,欢迎下次光临
谢谢您的10个包子!
请问您需要多少包子?
标签:res oms for msu %s code int sum import
原文地址:https://www.cnblogs.com/zhangsenzhen/p/9385244.html