标签:oss leetcode other arraylist class ons div ali ref
You are playing the following Flip Game with your friend: Given a string that contains only these two characters: + and -, you and your friend take turns to flip two consecutive "++" into "--". The game ends when a person can no longer make a move and therefore the other person will be the winner. Write a function to compute all possible states of the string after one valid move. For example, given s = "++++", after one move, it may become one of the following states: [ "--++", "+--+", "++--" ] If there is no valid move, return an empty list [].
若是连着的"++", 就把这段用"--"替代放到res中.
Note: 当i == s.length()-1走到最后一位时. s.substring(i+1), 不会out of index, 会返回"". 但再大就不行了.
Time Complexity: O(n). Space: O(1) regardless res.
public class Solution { public List<String> generatePossibleNextMoves(String s) { List<String> res = new ArrayList<>(); if(s == null || s.length()){ return res; } for (int i=1; i<s.length(); i++){ if(s.charAt(i-1) == ‘+‘ && s.charAt(i) == ‘+‘){ res.add(s.substring(0,i-1) + "--" + s.substring(i+1)); } } return res; } }
标签:oss leetcode other arraylist class ons div ali ref
原文地址:https://www.cnblogs.com/incrediblechangshuo/p/9388289.html