标签:roo das center amp tab ret lan turn .net
题目链接:https://cn.vjudge.net/problem/HDU-3065
跟上一道题是几乎一模一样,这次是统计关键词的出现次数
一个相当坑的地方,注意多组样例
套模版
改insert方法,这次我们指定每个关键词的idx
改query方法,统计value_counter(话说最近几天在用pandas,value_counts确实方便)
WA*n | 注意多组样例 |
WA | 注意用128大小的分支,用26个同时判断待匹配串的话会WA? |
AC |
#include <map>
#include <queue>
#include <cstdio>
#include <string>
#include <cstring>
using namespace std;
const int maxn=1000+20, maxw=50+20, maxl=2000000+20;
const int ACSize=maxn*maxw, maxitem=128;
char word[maxw], line[maxl];
map<int, string> tostr;
struct ACauto{
int next[ACSize][maxitem], fail[ACSize], cnt[ACSize];
int root, total;
int newnode(void){
for(int pos=0; pos<maxitem; pos++)
next[total][pos]=-1;
cnt[total]=0;
return total++;
}
void init(void){
total=0;
root=newnode();
}
int getPos(char ch){
return ch;
}
void insert(char buf[], int idx){
int now=root;
for(int i=0; buf[i]; i++){
int pos=getPos(buf[i]);
if(next[now][pos]==-1)
next[now][pos]=newnode();
now=next[now][pos];
}
cnt[now]=idx; //++itemCounter;
}
void build(void){
queue<int> que;
fail[root]=root;
for(int i=0; i<maxitem; i++)
if(next[root][i]==-1)
next[root][i]=root;
else{
fail[next[root][i]]=root;
que.push(next[root][i]);
}
while(!que.empty()){
int now=que.front(); que.pop();
for(int pos=0; pos<maxitem; pos++)
if(next[now][pos]==-1)
next[now][pos]=next[fail[now]][pos];
else{
fail[next[now][pos]]=next[fail[now]][pos];
que.push(next[now][pos]);
}
}
}
void query(char buf[], int counter[]){
int now=root;
for(int i=0; buf[i]; i++){
int pos=getPos(buf[i]);
// if (pos<0 || pos>=maxitem){pos=root; continue;}
now=next[now][pos];
for (int tmp=now; tmp!=root; tmp=fail[tmp]) if (cnt[tmp])
counter[cnt[tmp]]++;
}
}
}AC;
int main(void){
int m, n;
while (scanf("%d", &n)==1 &&n){
AC.init();
for (int i=1; i<=n; i++){
scanf("%s", word);
AC.insert(word, i);
tostr[i]=string(word);
}AC.build();
int counter[maxn]={0};
scanf("%s", line);
AC.query(line, counter);
for (int i=1; i<=n; i++) if (counter[i])
printf("%s: %d\n", tostr[i].c_str(), counter[i]);
}
return 0;
}
Time | Memory | Length | Lang | Submitted |
---|---|---|---|---|
234ms | 18004kB | 2417 | C++ | 2018-08-02 17:39:24 |
标签:roo das center amp tab ret lan turn .net
原文地址:https://www.cnblogs.com/tanglizi/p/9409342.html