UVA 11488 Hyper Prefix Sets (Trie)

标签：acm   algorithm   trie   数据结构   

http://uva.onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&page=show_problem&problem=2483

Hyper Prefix Sets

Prefix goodness of a set string islength of longest common prefix*number of strings in the set.For example the prefix goodness of theset {000,001,0011} is 6.You are given a set of binarystrings. Find the maximum prefixgoodness among all possible subsets of these binary strings.

Input

First line of the input contains T(≤20)the number of test cases. Each of the test cases start withn(≤50000) the number of strings. Eachof the next n lines contains a string containing only 0 andMaximum length of each of thesestring is 200.

Output

For each test case output the maximumprefix goodness among all possible subsets of n binarystrings.

Sample Input

4

4

0000

0001

10101

010

2

01010010101010101010

11010010101010101010

3

010101010101000010001010

010101010101000010001000

010101010101000010001010

5

01010101010100001010010010100101

01010101010100001010011010101010

00001010101010110101

0001010101011010101

00010101010101001

Output for Sample Input

6

20

66

44

Problem Setter : Abdullah Al Mahmud

Special Thanks : Manzurur Rahman Khan

题意：
给出N个字符串，要求选出若干个，使得选中的字符串的公共前缀长度与选中字符串的个数的乘积最大。
分析：
简单粗暴的Trie模板题。
对于Tire中的每一个结点添加两个信息：该结点的深度及该结点杯访问的次数，最后求出这两个信息的最大值就行了，边加入字符串边维护就行。

/*
 *
 * Author : fcbruce
 *
 * Time : Sat 04 Oct 2014 09:17:50 PM CST
 *
 */
#include <cstdio>
#include <iostream>
#include <sstream>
#include <cstdlib>
#include <algorithm>
#include <ctime>
#include <cctype>
#include <cmath>
#include <string>
#include <cstring>
#include <stack>
#include <queue>
#include <list>
#include <vector>
#include <map>
#include <set>
#define sqr(x) ((x)*(x))
#define LL long long
#define itn int
#define INF 0x3f3f3f3f
#define PI 3.1415926535897932384626
#define eps 1e-10

#ifdef _WIN32
  #define lld "%I64d"
#else
  #define lld "%lld"
#endif

#define maxm 2
#define maxn 5000007

using namespace std;

struct Trie
{
  int ch[maxn][maxm];
  int deep[maxn];
  int cnt[maxn][maxm];
  int MAX;
  int sz;

  Trie()
  {
    sz=1;
    deep[0]=0;
    MAX=0;
    memset(cnt[0],0,sizeof cnt[0]);
    memset(ch[0],0,sizeof ch[0]);
  }

  void clear()
  {
    sz=1;
    deep[0]=0;
    MAX=0;
    memset(cnt[0],0,sizeof cnt[0]);
    memset(ch[0],0,sizeof ch[0]);
  }

  int idx(const char ch)
  {
    return ch-'0';
  }

  void insert(const char *s)
  {
    for (int i=0,j=0;s[i]!='\0';i++)
    {
      int c=idx(s[i]);
      if (ch[j][c]==0)
      {
        memset(ch[sz],0,sizeof ch[sz]);
        memset(cnt[sz],0,sizeof cnt[sz]);
        deep[sz]=i+1;
        ch[j][c]=sz++;
      }
      j=ch[j][c];
      cnt[j][c]++;
      MAX=max(MAX,deep[j]*cnt[j][c]);
    }
  }
}trie;

char str[233];

int main()
{
#ifdef FCBRUCE
  freopen("/home/fcbruce/code/t","r",stdin);
#endif // FCBRUCE

  int T_T;
  scanf("%d",&T_T);
  
  while (T_T--)
  {
    trie.clear();

    int n;
    scanf("%d",&n);
    
    for (int i=0;i<n;i++)
    {
      scanf("%s",str);
      trie.insert(str);
    }

    printf("%d\n",trie.MAX);
  }


  return 0;
}

UVA 11488 Hyper Prefix Sets (Trie)

标签：acm   algorithm   trie   数据结构   

原文地址：http://blog.csdn.net/u012965890/article/details/39783285