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[LeetCode] 680. Valid Palindrome II_Easy tag: Two Pointers

时间:2018-08-15 01:25:26      阅读:168      评论:0      收藏:0      [点我收藏+]

标签:span   can   point   class   character   思路   poi   elf   max   

Given a non-empty string s, you may delete at most one character. Judge whether you can make it a palindrome.

Example 1:

Input: "aba"
Output: True

 

Example 2:

Input: "abca"
Output: True
Explanation: You could delete the character ‘c‘.

 

Note:

  1. The string will only contain lowercase characters a-z. The maximum length of the string is 50000.

 

题目思路就是正常的用two pointers去遍历s, 然后如果有不一样的, 要么把l + = 1, 要么把r -= 1 , 然后如果这两个中有一个是palindrome, 那么就符合.

 

Code:

class Solution:
    def palindrome2(self, s): # len(s) >= 1
        l, r = 0, len(s)-1
        def helper(l, r, s):
            while l < r:
                if s[l] == s[r]:
                    l += 1
                    r -=  1
                else:
                    return False
            return True
        while l <r:
            if s[l] == s[r]:
                l += 1
                r -= 1
            else:
                return helper(l+1, r, s) or helper(l, r-1, s)
        return True

 

[LeetCode] 680. Valid Palindrome II_Easy tag: Two Pointers

标签:span   can   point   class   character   思路   poi   elf   max   

原文地址:https://www.cnblogs.com/Johnsonxiong/p/9479037.html

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