NYOJ 迷宫寻宝(一)

# include<iostream>
# include<string>
# include<string.h>
# include<queue>
# include<stdio.h>
# include<math.h>
#include <algorithm>
using namespace std;
char d[30][30]; 
int a[5],b[5];
struct Node
{
    int x,y;
    int num;
}node,temp,f[4];
queue<Node> q,q1;
void bfs(int x,int y,int m,int n)
{
    int k;
    node.x = x;
    node.y = y;
    q.push(node);
    d[x][y] = ‘0‘;
    while(!q.empty())
    {
        temp = q.front();
        q.pop();
        for(int i=0;i<4;i++)
        {
            int t1,t2;
            t1 = temp.x + f[i].x;
            t2 = temp.y + f[i].y;
            if(t1<0 ||t1>=m || t2<0 || t2>=n)
                continue;
            if(d[t1][t2] == ‘G‘)
            {
                printf("YES\n");
                return;
            }
            else if(d[t1][t2] == ‘0‘ || d[t1][t2] == ‘X‘)
            {
                continue;
            }
            else if(d[t1][t2] == ‘A‘ || d[t1][t2] == ‘B‘ || d[t1][t2] == ‘C‘ || d[t1][t2] == ‘D‘ || d[t1][t2] == ‘E‘)
            {
                k = d[t1][t2] - ‘A‘;
                if(b[k]>=a[k] && a[k]!=0)
                {
                    d[t1][t2] = ‘0‘;
                    node.x = t1;
                    node.y = t2;
                    q.push(node);
                }
                else 
                {
                    node.x = t1;
                    node.y = t2;
                    node.num = k;
                    q1.push(node);
                }
            }
            else if(d[t1][t2] == ‘.‘ || d[t1][t2] == ‘a‘ || d[t1][t2] == ‘b‘ || d[t1][t2] == ‘c‘ || d[t1][t2] == ‘d‘ || d[t1][t2] == ‘e‘)
            {
                
                if(d[t1][t2]!=‘.‘)
                {
                    k = d[t1][t2] - ‘a‘;
                    b[k]++;
                }
                d[t1][t2] = ‘0‘;
                node.x = t1;
                node.y = t2;
                q.push(node);
            }
            
        }
        
        if(q.empty()==true && q1.empty()!=true)
        {
            k = q1.size();
            for(int i=0;i<k;i++)
            {
                temp = q1.front();
                q1.pop();
                if(b[temp.num]>=a[temp.num] && a[temp.num]!=0)
                {
                    q.push(temp);
                    d[temp.x][temp.y] = ‘0‘;
                }
                else
                {
                    q1.push(temp);
                }
            }
        }

    }
    //要清空q1 
    while(!q1.empty())
    {
        q1.pop();
    }
    printf("NO\n");
}
int main()
{
      int n,m,i,j,x,y;
      f[0].x=0;f[0].y=1;
      f[1].x=0;f[1].y=-1;
      f[2].x=1;f[2].y=0;
      f[3].x=-1;f[3].y=0;
      scanf("%d %d",&m,&n);
      getchar();
      while(n!=0 || m!=0)
      {
          for(i=0;i<5;i++)
        {
            a[i] = 0;
            b[i] = 0;
        }
        
        //要重置d数组
        for(i=0;i<30;i++)
            for(j=0;j<30;j++)
                d[i][j]=‘0‘; 
          for(i=0;i<m;i++)
          {
              for(j=0;j<n;j++)
            {
                scanf("%c",&d[i][j]);    
                if(d[i][j]==‘S‘)    
                {
                    x = i;
                    y = j;
                }
                if(d[i][j]==‘a‘)        a[0]++; 
                else if(d[i][j]==‘b‘)    a[1]++;  
                else if(d[i][j]==‘c‘)    a[2]++;  
                else if(d[i][j]==‘d‘)    a[3]++;  
                else if(d[i][j]==‘e‘)    a[4]++;  
            }    
            getchar();    
        }
        
        bfs(x,y,m,n);
        
        
        /* 
        for(i=0;i<m;i++)
          {
              for(j=0;j<n;j++)
            {
                printf("%c",d[i][j]);          
            }    
            printf("\n");
        }
        */ 
        scanf("%d %d",&m,&n);
        
        //WA原因 少了这句话
        getchar();
    }
    return 0;
}