标签:fir 相同 linker cto pre continue tor fine txt
题意:
两个小朋友可以任选一块草地点火,草地可以不同,也可以相同,问最少的烧光草地的时间。
思路:
一开始看到这个以为是联通块计数,没想到这道题通过枚举两个起始点作为队列的初始点,每次跑一边bfs即可。
#include <algorithm> #include <iterator> #include <iostream> #include <cstring> #include <cstdlib> #include <iomanip> #include <bitset> #include <cctype> #include <cstdio> #include <string> #include <vector> #include <cmath> #include <queue> #include <list> #include <map> #include <set> using namespace std; //#pragma GCC optimize(3) //#pragma comment(linker, "/STACK:102400000,102400000") //c++ #define lson (l , mid , rt << 1) #define rson (mid + 1 , r , rt << 1 | 1) #define debug(x) cerr << #x << " = " << x << "\n"; #define pb push_back #define pq priority_queue typedef long long ll; typedef unsigned long long ull; typedef pair<ll ,ll > pll; typedef pair<int ,int > pii; typedef pair<int,pii> p3; //priority_queue<int> q;//这是一个大根堆q //priority_queue<int,vector<int>,greater<int> >q;//这是一个小根堆q #define fi first #define se second //#define endl ‘\n‘ #define OKC ios::sync_with_stdio(false);cin.tie(0) #define FT(A,B,C) for(int A=B;A <= C;++A) //用来压行 #define REP(i , j , k) for(int i = j ; i < k ; ++i) //priority_queue<int ,vector<int>, greater<int> >que; const ll mos = 0x7FFFFFFFLL; //2147483647 const ll nmos = 0x80000000LL; //-2147483648 const int inf = 0x3f3f3f3f; const ll inff = 0x3f3f3f3f3f3f3f3fLL; //18 const int mod = 1e9+7; const double PI=acos(-1.0); // #define _DEBUG; //*// #ifdef _DEBUG freopen("input", "r", stdin); // freopen("output.txt", "w", stdout); #endif /*-----------------------showtime----------------------*/ const int maxn = 20; int n,m; string mp[maxn]; int dp[maxn][maxn]; int nt[4][4] = { {1,0},{0,1},{-1,0},{0,-1}, }; struct node { int x,y,step; }q[maxn*maxn]; int mx,tot; void bfs(node a,node b){ mx = 0; for(int i=0; i<maxn; i++){ for(int j=0; j<maxn; j++)dp[i][j] = inf; } queue<node>que; que.push(a); if(a.x!=b.x||a.y!=b.y)que.push(b); dp[a.x][a.y] = 0; dp[b.x][b.y] = 0; while(!que.empty()){ int x = que.front().x,y = que.front().y,s = que.front().step; que.pop(); for(int i=0 ; i<4; i++){ int nx = x + nt[i][0],ny = y + nt[i][1]; if(nx < 0||nx >=n || ny <0||ny>=m)continue; if(mp[nx][ny]==‘.‘)continue; if(dp[nx][ny] > s + 1){ dp[nx][ny] = s + 1; mx = max(mx,s+1); node tmp={nx,ny,s+1}; que.push(tmp); } } } } void solve(){ cin>>n>>m; for(int i=0; i<n; i++){ cin>>mp[i]; } int cnt = 0,ans = inf; for(int i=0; i<n ; i++){ for(int j=0; j<m; j++){ if(mp[i][j]==‘#‘){ q[++cnt].x = i; q[cnt].y = j; q[cnt].step = 0; } } } for(int i=1; i<=cnt; i++) { for(int j=i; j<=cnt; j++){ bfs(q[i],q[j]); int flag = 1; for(int x = 0; x < n; x++){ for(int y = 0; y<m; y++){ if(dp[x][y] >=inf && mp[x][y] == ‘#‘)flag= 0; } } if(flag)ans = min(ans, mx); } } if(ans < inf)cout<<ans<<endl; else cout<<-1<<endl; } int main(){ int T; cin>>T; for(int t=1;t<=T;t++){ cout<<"Case "<<t<<": "; solve(); } return 0; }
标签:fir 相同 linker cto pre continue tor fine txt
原文地址:https://www.cnblogs.com/ckxkexing/p/9500678.html