标签:pop operator size mem div bsp tle i++ targe
本道题我没打出来,因为c++字符串处理不会用,后来托这个网站的福,打出来了,用了高精度类,300多行,应该是我打过最长的代码了吧。
#include<bits/stdc++.h> using namespace std; class Int{ #define BASE 1000000000 public: typedef long long value; void New(size_t l){ if (a!=NULL)delete[] a;a=new value[l]; len=1;a[0]=0;sign=1; } Int():a(NULL),base(BASE){New(1);} Int(value x):a(NULL),base(BASE){New(1);*this=x;} Int(value x,value _base):a(NULL),base(_base){New(1);*this=x;} Int(const Int &B):a(NULL),base(BASE){New(1);*this=B;} ~Int(){delete[] a;} Int& operator =(value x){ size_t l=1;for (value x1=max(x,-x);x1>=base;++l,x1/=base);New(l); if (x<0)x=-x,sign=0;else sign=1; len=0;while (x)a[len++]=x%base,x/=base; if (!len)a[len++]=0; return *this; } Int& operator =(const Int &A){ New(A.len);len=A.len;memcpy(a,A.a,sizeof(value)*len); base=A.base;sign=A.sign;return *this; } friend Int operator -(Int A){A.sign=1-A.sign;return A;} bool operator !(){if (len==1&&a[0]==0)return 1;else return 0;} friend Int operator +(Int A,Int B){ if (A.sign!=B.sign){B.sign=1-B.sign;return A-B;} if (A.base!=B.base) if (A.base>B.base)B.set_base(A.base); else A.set_base(B.base); Int res;res.set_base(A.base); int len=A.len>B.len?A.len:B.len; res.New(len+1);res.sign=A.sign; memset(res.a,0,(len+1)*sizeof(value)); for (int i=0;i<len;++i){ if (i<A.len)res.a[i]+=A.a[i]; if (i<B.len)res.a[i]+=B.a[i]; } for (int i=0;i<len;++i) if (res.a[i]>=res.base)++res.a[i+1],res.a[i]-=res.base; if (res.a[len])res.len=len+1;else res.len=len; if (!res)res.sign=1;return res; } friend Int operator -(Int A,Int B){ if (A.sign!=B.sign){B.sign=1-B.sign;return A+B;} if (A.base!=B.base) if (A.base>B.base)B.set_base(A.base); else A.set_base(B.base); if (small(A,B))swap(A,B),A.sign=1-A.sign; Int res;res.set_base(A.base); int len=A.len>B.len?A.len:B.len; res.New(len);res.sign=A.sign; memset(res.a,0,len*sizeof(value)); for (int i=0;i<len;++i){ if (i>=B.len)res.a[i]+=A.a[i]; else res.a[i]+=A.a[i]-B.a[i]; if (res.a[i]<0)res.a[i]+=res.base,--res.a[i+1]; } while (len>1&&!res.a[len-1])--len;res.len=len; if (!res)res.sign=1;return res; } friend Int operator *(Int A,Int B){ if (A.base!=B.base) if (A.base>B.base)B.set_base(A.base); else A.set_base(B.base); Int res;res.set_base(A.base); int len=A.len+B.len; res.New(len);res.sign=(A.sign==B.sign); memset(res.a,0,len*sizeof(value)); for (int i=0;i<A.len;++i) for (int j=0;j<B.len;++j){ res.a[i+j]+=A.a[i]*B.a[j]; res.a[i+j+1]+=res.a[i+j]/res.base; res.a[i+j]%=res.base; } /* for (int i=0;i<A.len;++i) for (int j=0;j<B.len;++j)res.a[i+j]+=A.a[i]*B.a[j]; for (int i=0;i<len-1;++i)res.a[i+1]+=res.a[i]/res.base,res.a[i]%=res.base; */ while (len>1&&!res.a[len-1])--len;res.len=len; return res; } friend pair<Int,Int> divide(Int A,Int B){ if (!B){puts("error:div zero!");for (;;);} if (A.base!=B.base) if (A.base>B.base)B.set_base(A.base); else A.set_base(B.base); if (small(A,B))return make_pair(Int(0),A); Int C,D;C.set_base(A.base);D.set_base(A.base);C.New(A.len);C.len=A.len; bool Csign=(A.sign==B.sign),Dsign=A.sign;A.sign=B.sign=1; for (int i=A.len-1;i>=0;--i){ C.a[i]=0;D=D*D.base;D.a[0]=A.a[i]; int l=0,r=A.base-1,mid; while (l<r){ mid=(l+r+1)>>1; if (small(B*mid,D+1))l=mid; else r=mid-1; } C.a[i]=l;D=D-B*l; } C.sign=Csign;D.sign=Dsign;if (!D)D.sign=1; while (C.len>1&&!C.a[C.len-1])--C.len; return make_pair(C,D); } Int operator /(value x){ if (!x){puts("error:div zero!");for (;;);} value d=0;Int res;res.set_base(base);res.New(len);res.len=len; if (x<0)x=-x,res.sign=(sign==0); else res.sign=(sign==1); for (int i=len-1;i>=0;--i) d=d*base+a[i],res.a[i]=d/x,d%=x; while (res.len>1&&!res.a[res.len-1])--res.len; return res; } Int operator %(value x){ value d=0;if (x<0)x=-x; for (int i=len-1;i>=0;--i)d=(d*base+a[i])%x; return d; } friend Int abs(Int A){A.sign=1;return A;} friend bool small(Int A,Int B){ if (A.base!=B.base) if (A.base>B.base)B.set_base(A.base); else A.set_base(B.base); if (A.len!=B.len)return A.len<B.len; for (int i=A.len-1;i>=0;--i) if (A.a[i]!=B.a[i])return A.a[i]<B.a[i]; return 0; } friend bool operator <(Int A,Int B){ if (A.sign!=B.sign)return A.sign<B.sign; return A.sign==1?small(A,B):small(B,A); } friend bool operator ==(Int A,Int B){ if (A.base!=B.base) if (A.base>B.base)B.set_base(A.base); else A.set_base(B.base); if (A.sign!=B.sign||A.len!=B.len)return 0; for (int i=0;i<A.len;++i)if (A.a[i]!=B.a[i])return 0; return 1; } friend bool operator !=(Int A,Int B){return !(A==B);} friend bool operator >(Int A,Int B){return !(A<B||A==B);} friend bool operator <=(Int A,Int B){return A<B||A==B;} friend bool operator >=(Int A,Int B){return A>B||A==B;} Int operator /(Int B){return divide(*this,B).first;} Int operator %(Int B){return divide(*this,B).second;} Int& operator +=(Int B){*this=*this+B;return *this;} Int& operator -=(Int B){*this=*this-B;return *this;} Int& operator *=(Int B){*this=*this*B;return *this;} Int& operator /=(Int B){*this=*this/B;return *this;} Int& operator %=(Int B){*this=*this%B;return *this;} Int& operator ++(){*this=*this+1;return *this;} Int& operator --(){*this=*this-1;return *this;} Int operator ++(int){Int res(*this);*this=*this+1;return res;} Int operator --(int){Int res(*this);*this=*this-1;return res;} Int operator +(value x){return *this+Int(x,this->base);} Int operator -(value x){return *this-Int(x,this->base);} Int operator *(value x){return *this*Int(x,this->base);} //Int operator /(value x){Int T;T=x;return *this/T;} //Int operator %(value x){Int T;T=x;return *this%T;} Int& operator *=(value x){*this=*this*x;return *this;} Int& operator +=(value x){*this=*this+x;return *this;} Int& operator -=(value x){*this=*this-x;return *this;} Int& operator /=(value x){*this=*this/x;return *this;} Int& operator %=(value x){*this=*this%x;return *this;} bool operator ==(value x){return *this==Int(x,this->base);} bool operator !=(value x){return *this!=Int(x,this->base);} bool operator <=(value x){return *this<=Int(x,this->base);} bool operator >=(value x){return *this>=Int(x,this->base);} bool operator <(value x){return *this<Int(x,this->base);} bool operator >(value x){return *this>Int(x,this->base);} friend Int gcd(Int x,Int y){ Int t;int cnt=0; while (1){ if (x<y)t=x,x=y,y=t; if (y==0){ while (cnt--)x*=2; return x; } if (x%2==0&&y%2==0)x/=2,y/=2,++cnt; else if (x%2==0)x/=2; else if (y%2==0)y/=2; else {t=x;x=y;y=t-y;} } } void to_arr(char *c){ char *c1=c; for (int i=0;i<len-1;++i) for (value x=a[i],b=base/10;b>=1;b/=10)*c1++=‘0‘+x%10,x/=10; for (value x=a[len-1];x>0;x/=10)*c1++=‘0‘+x%10; if (len==1&&a[len]==0)*c1++=‘0‘; if (sign==0)*c1++=‘-‘;*c1=0;reverse(c,c1); } void from_arr(char *c){ size_t base_l=get_basel(),b=1;int cl=strlen(c);value x=0; New((cl+base_l-1)/base_l);len=0; if (*c==‘-‘)sign=0,++c,--cl;else sign=1; while (--cl>=0){ x+=(c[cl]-‘0‘)*b;b*=10;if (b==base)a[len++]=x,x=0,b=1; } if (!len||x)a[len++]=x; while (len>1&&!a[len-1])--len; } void set_base(int _base){ if (base==_base)return; char *c=new char[len*get_basel()+1]; to_arr(c);base=_base;from_arr(c); delete[] c; } void set_basel(int _l){ size_t _base=1;while (_l--)_base*=10;set_base(_base); } void read(){ vector<char> s;char ch; scanf(" %c",&ch);if (ch==‘-‘)s.push_back(‘-‘),ch=getchar(); for (;ch>=‘0‘&&ch<=‘9‘;ch=getchar())s.push_back(ch); char *c=new char[s.size()+1]; for (int i=0;i<s.size();++i)c[i]=s[i];c[s.size()]=0; from_arr(c);delete[] c; if (!*this)this->sign=1; } void print(){ if (!sign)putchar(‘-‘); printf("%d",int(a[len-1])); for (int i=len-2;i>=0;--i){ for (int j=base/10;j>=10;j/=10) if (a[i]<j)putchar(‘0‘); else break; printf("%d",(int)a[i]); } } string inttostring(int x){ stringstream a; a<<x; string b; a>>b; return b; } string prin(){ string ss=""; if (!sign) ss+=‘-‘; ss+=inttostring(a[len-1]); for (int i=len-2;i>=0;--i){ for (int j=base/10;j>=10;j/=10) if (a[i]<j) ss+=‘0‘; else break; ss+=inttostring(a[i]); } return ss; } void println(){print();putchar(‘\n‘);} private: value *a,base;int len;bool sign; //0="-" size_t get_basel()const { size_t res=0;for (int b=base/10;b>=1;b/=10,++res); return res; } #undef BASE };//高精类 string s,ans; Int a,c=1,ll=1,l=1; int b,k,ppop[3010]; int main(){ freopen("exp.in","r",stdin); freopen("exp.out","w",stdout); cin>>s; cin>>b; int tp=0;int len=s.size();int lls; for(int i=0;i<len;i++){ if(s[i]==‘.‘) lls=i; } for(int i=lls+1;i<len;i++){ ppop[tp++]=s[i]; } tp--; while(ppop[tp]==‘0‘) tp--; k=s.length(); while(s[k-1]==‘0‘){s.erase(k-1,1);k--;} if (s[0]==‘.‘) s=‘0‘+s; for (int i=0;i<s.length();i++) { if (s[i]==‘.‘) l*=10; else if (l>=10) a=a*10+s[i]-‘0‘;else a=a*10+s[i]-‘0‘,l*=10; } for (int i=1;i<=b;i++) c=c*a,ll=ll*l;//c为去小数点的数,l为小数点pow(10,位数),c/l为answer,但有精度问题。 string qwq; qwq=c.prin(); string pwp; pwp=ll.prin(); int us=(tp+1)*b; us=qwq.size()-us;//找小数点位数 bool bi=0; // us--; if (us<0) putchar(‘.‘),bi=1; while(us<0) { putchar(‘0‘); us++; } for(int i=0;i<qwq.size();i++) { if(i==us&&bi==0) putchar(‘.‘);//到小数点输出小数点,否则输出数字 putchar(qwq[i]); } return 0; }
标签:pop operator size mem div bsp tle i++ targe
原文地址:https://www.cnblogs.com/GREED-VI/p/9501488.html