标签：乘法   bar   end   def   n+1   递归   \n   code   int   

写代码完成99乘法表

# 1 * 1 = 1
# 2 * 1 = 2 2 * 2 = 4
# 3 * 1 = 3 3 * 2 = 6 3 * 3 = 9
# ......
# 9 * 1 = 9 9 * 2 = 18 9 * 3 = 27 9 * 4 = 36 9 * 5 = 45 9 * 6 = 54 9 * 7 = 63 9 * 8 = 72 9 * 9 = 81

递归的方法：

def bar(n):
    for i in range(1,n+1):
        res = "{} * {} = {}".format(n, i, n * i)
        print(res,end="  ")
    if n < 9:
        n += 1
        print("\n")
        bar(n)
bar(1)

9*9乘法口诀

标签：乘法   bar   end   def   n+1   递归   \n   code   int   

原文地址：https://www.cnblogs.com/xiayuhao/p/9520335.html