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leetcode -- Clone Graph

时间:2014-10-07 00:20:21      阅读:208      评论:0      收藏:0      [点我收藏+]

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不要晃荡,找准方向

[问题描述]

Clone an undirected graph. Each node in the graph contains a label and a list of its neighbors.


OJ‘s undirected graph serialization:

Nodes are labeled uniquely.

We use # as a separator for each node, and , as a separator for node label and each neighbor of the node.

 

As an example, consider the serialized graph {0,1,2#1,2#2,2}.

The graph has a total of three nodes, and therefore contains three parts as separated by #.

  1. First node is labeled as 0. Connect node 0 to both nodes 1 and 2.
  2. Second node is labeled as 1. Connect node 1 to node 2.
  3. Third node is labeled as 2. Connect node 2 to node 2 (itself), thus forming a self-cycle.

 

Visually, the graph looks like the following:

       1
      /      /       0 --- 2
         /          \_/

[解题思路]
深度优先遍历
 1 UndirectedGraphNode *Solution::cloneGraph(UndirectedGraphNode *node){
 2     if (node == NULL)
 3         return NULL;
 4     map<UndirectedGraphNode*, UndirectedGraphNode*> visited;
 5     queue<UndirectedGraphNode*> bfs_q;
 6     visited[node] = new UndirectedGraphNode(node->label);
 7     bfs_q.push(node);
 8     while(!bfs_q.empty()){
 9         UndirectedGraphNode* tmp = bfs_q.front(); bfs_q.pop();
10         for (auto k : tmp->neighbors){
11             if (visited.find(k) == visited.end()){
12                 UndirectedGraphNode* t = new UndirectedGraphNode(k->label);
13                 visited[k] = t;
14                 visited[tmp]->neighbors.push_back(t);
15                 bfs_q.push(k);
16             }
17             else{
18                 visited[tmp]->neighbors.push_back(visited[k]);
19             }
20         }
21     }
22     return visited[node];
23 }

 



leetcode -- Clone Graph

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原文地址:http://www.cnblogs.com/taizy/p/4008713.html

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