标签:ios 知识 准备 test The oid pack turn 网易
网易面试挂了,伤心。
一面面试官不是搞技术的,二面面试官搞ios,全程不问JVM,并发的知识,运气真差
而且手撸代码硬伤,没得编译
准备先在IDE敲一遍,在再纸上面写一遍。
1 package com.qiuzhao.test; 2 3 import java.util.PriorityQueue; 4 import java.util.Queue; 5 6 /** 7 * @Auther: Chang 8 * @Date: 2018/8/27 9 */ 10 public class topK { 11 public static void main(String[] args) { 12 13 int[] a = {489, 500, 111, 100, 2, 7, 3, 8, 66, 888}; 14 int k = 3; 15 // 第一种 推排序 16 prioritySort(a, k); 17 // 第二种 快速排序 18 quickSort(a, k); 19 } 20 21 // 堆排序 int[] a = {489, -5, 111, 100, 2, 7, 3, 8, 66, 88}; 22 private static void prioritySort(int[] a, int k) { 23 Queue<Integer> pq = new PriorityQueue<>(k); 24 for (int i = 0; i < a.length; i++) { 25 int n = pq.size(); 26 if (n >= k && a[i] > pq.peek()) { 27 pq.poll(); 28 } 29 n = pq.size(); 30 if (n < k) pq.add(a[i]); 31 } 32 pq.forEach(x -> System.out.print(x + " ")); 33 System.out.println(); 34 } 35 36 private static void quickSort(int[] a, int k) { 37 38 int left = 0; 39 int right = a.length - 1; 40 int mid = partition(a, left, right); 41 while (mid != k) { 42 if (mid > k) { 43 right = mid - 1; 44 mid = partition(a, left, right); 45 } else { 46 left = mid + 1; 47 mid = partition(a, left, right); 48 } 49 } 50 for (int i = 0; i < mid; i++) { 51 System.out.print(a[i] + " "); 52 } 53 System.out.println(); 54 } 55 56 private static int partition(int[] a, int left, int right) { 57 58 int temp = a[left]; 59 while (left < right) { 60 while (left < right && a[right] <= temp) right--; 61 a[left] = a[right]; 62 while (left < right && a[left] >= temp) left++; 63 a[right] = a[left]; 64 } 65 a[left] = temp; 66 return left; 67 } 68 }
标签:ios 知识 准备 test The oid pack turn 网易
原文地址:https://www.cnblogs.com/wenbochang/p/9540794.html