242. Valid Anagram

 1 //easy
 2 //注意字符串长度可能不一样
 3 
 4 class Solution {
 5     public boolean isAnagram(String s, String t) {
 6         if(s.length() != t.length()) return false;
 7         char[] arr1 = s.toCharArray();
 8         char[] arr2 = t.toCharArray();
 9         Arrays.sort(arr1);
10         Arrays.sort(arr2);
11         for(int i = 0; i < arr1.length; i++) {
12             if(arr1[i] != arr2[i]) return false;
13         }
14         return true;
15         
16     }
17 }