标签:pac pre return namespace == ios ace pad min
考虑到题中说明,AB均采用最优策略,通过最大最小搜索完成。
#include<iostream>
using namespace std;
int pad[9];
#define max(a,b) ((a)>(b)?(a):(b))
#define min(a,b) ((a)<(b)?(a):(b))
int status() {
for (int i = 0; i<3; i++) {
if (pad[i * 3] != 0 && pad[i * 3] == pad[i * 3 + 1] && pad[i*3] == pad[i * 3 + 2]) {
return pad[i * 3];
}
if (pad[i] != 0 && pad[i] == pad[i + 3] && pad[i] == pad[i + 6]) {
return pad[i];
}
}
if (pad[4] != 0 && pad[0] == pad[4] && pad[4] == pad[8]) {
return pad[4];
}
if (pad[4] != 0 && pad[2] == pad[4] && pad[4] == pad[6]) {
return pad[4];
}
return 0;
}
int minmax(int depth) {
if (depth >9) {
return 0;
}
int a = status();//current
if (a != 0) {
return (9 - depth + 1)*(a == 1 ? 1 : -1);
}
if (depth == 9) {
return 0;
}
if (depth % 2 == 0) {//a.Going to choose the maxScore;
int maxScore = -10;
for (int i = 0; i<9; i++) {
if (pad[i] == 0) {
pad[i] = 1;
maxScore = max(maxScore, minmax(depth + 1));
pad[i] = 0;
}
}
return maxScore;
}
else {//B . Going to get min;
int minScore = 10;
for (int i = 0; i<9; i++) {
if (pad[i] == 0) {
pad[i] = 2;
minScore = min(minScore, minmax(depth + 1));
pad[i] = 0;
}
}
return minScore;
}
}
int main() {
int T;
cin >> T;
int depth = 0;
while (T-->0) {
depth = 0;
for (int i = 0; i<9; i++) {
cin >> pad[i];
if (pad[i]) {
depth++;
}
}
if (depth == 0) {
cout << 0 << endl;
}
else
{
cout << minmax(depth) << endl;
}
}
return 0;
}
标签:pac pre return namespace == ios ace pad min
原文地址:https://www.cnblogs.com/SilverChen/p/9567519.html