标签:HERE extra seq names als ica pre scanf sort
This time your job is to fill a sequence of N positive integers into a spiral matrix in non-increasing order. A spiral matrix is filled in from the first element at the upper-left corner, then move in a clockwise spiral. The matrix has m rows and ncolumns, where m and n satisfy the following: m×n must be equal to N; m≥n; and m?n is the minimum of all the possible values.
Each input file contains one test case. For each case, the first line gives a positive integer N. Then the next line contains Npositive integers to be filled into the spiral matrix. All the numbers are no more than 1. The numbers in a line are separated by spaces.
For each test case, output the resulting matrix in m lines, each contains n numbers. There must be exactly 1 space between two adjacent numbers, and no extra space at the end of each line.
12
37 76 20 98 76 42 53 95 60 81 58 93
98 95 93 42 37 81 53 20 76 58 60 76
#include<iostream> #include<vector> #include<algorithm> using namespace std; bool cmp(int a, int b){ return a>b; } int main(){ int N, i, j, n; scanf("%d", &N); for(i=1; i*i<N+1; i++) if(N%i==0) n=i; vector<vector<int> > arr(N/n, vector<int>(n)), vis(N/n, vector<int>(n, false)); vector<int> v(N); for(i=0; i<N; i++) scanf("%d", &v[i]); sort(v.begin(), v.end(), cmp); int x=0, y=0, dir=0; for(i=0; i<N; i++){ if(dir==0){ if(y==n || vis[x][y]){ dir=1; y--; x++; i--; }else{ arr[x][y] = v[i]; vis[x][y] = true; y++; } }else if(dir==1){ if(x==N/n || vis[x][y]){ x--; y--; dir=2; i--; }else{ arr[x][y] = v[i]; vis[x][y] = true; x++; } }else if(dir==2){ if(y==-1 || vis[x][y]){ y++; x--; dir=3; i--; }else{ arr[x][y] = v[i]; vis[x][y] = true; y--; } }else{ if(x==-1 || vis[x][y]){ dir=0; x++; y++; i--; }else{ arr[x][y] = v[i]; vis[x][y] = true; x--; } } } for(i=0; i<N/n; i++){ cout<<arr[i][0]; for(j=1; j<n; j++) cout<<" "<<arr[i][j]; cout<<endl; } return 0; }
标签:HERE extra seq names als ica pre scanf sort
原文地址:https://www.cnblogs.com/mr-stn/p/9574646.html