标签:stdin can scan text car tor htm ups Fix
The task is really simple: given N exits on a highway which forms a simple cycle, you are supposed to tell the shortest distance between any pair of exits.
Each input file contains one test case. For each case, the first line contains an integer N (in [3,10?5??]), followed by N integer distances D?1?? D?2?? ? D?N??, where D?i?? is the distance between the i-th and the (i+1)-st exits, and D?N?? is between the N-th and the 1st exits. All the numbers in a line are separated by a space. The second line gives a positive integer M (≤10?4??), with M lines follow, each contains a pair of exit numbers, provided that the exits are numbered from 1 to N. It is guaranteed that the total round trip distance is no more than 10?7??.
For each test case, print your results in M lines, each contains the shortest distance between the corresponding given pair of exits.
5 1 2 4 14 9
3
1 3
2 5
4 1
3
10
7
1 #include <iostream> 2 #include <algorithm> 3 #include <cstdio> 4 #include <cstring> 5 #include <map> 6 #include <stack> 7 #include <vector> 8 #include <queue> 9 #include <set> 10 #define LL long long 11 using namespace std; 12 const int MAX = 4e5 + 10; 13 14 int N, D[MAX], pre[MAX], M, ans, a, b, ans2; 15 struct node 16 { 17 int L, R, val; 18 }P[MAX]; 19 20 void build(int dep, int l, int r) 21 { 22 P[dep].L = l, P[dep].R = r, P[dep].val = 0; 23 if (l == r) 24 { 25 pre[l] = dep; 26 return; 27 } 28 int mid = (l + r) >> 1; 29 build(dep << 1, l, mid); 30 build((dep << 1) + 1, mid + 1, r); 31 } 32 33 void update(int r, int b) 34 { 35 P[r].val += b; 36 if (r == 1) return ; 37 update(r >> 1, b); 38 } 39 40 void query(int dep, int l, int r) 41 { 42 if (P[dep].L == l && P[dep].R == r) 43 { 44 ans += P[dep].val; 45 return ; 46 } 47 int mid = (P[dep].L + P[dep].R) >> 1; 48 if (r <= mid) query(dep << 1, l, r); 49 else if (l > mid) query((dep << 1) + 1, l, r); 50 else 51 { 52 query(dep << 1, l, mid); 53 query((dep << 1) + 1, mid + 1, r); 54 } 55 } 56 57 int main() 58 { 59 // freopen("Date1.txt", "r", stdin); 60 scanf("%d", &N); 61 build(1, 1, N); 62 for (int i = 1; i <= N; ++ i) 63 { 64 scanf("%d", &D[i]); 65 update(pre[i], D[i]); 66 } 67 68 scanf("%d", &M); 69 while (M --) 70 { 71 ans = 0; 72 scanf("%d%d", &a, &b); 73 if (b < a) swap(a, b); 74 if (a == b - 1) ans += D[a]; 75 else query(1, a, b - 1); 76 ans2 = ans, ans = 0; 77 78 if (a - 1 == 1) ans += D[1]; 79 else if (a - 1 > 1) query(1, 1, a - 1); 80 if (b == N) ans += D[N]; 81 else query(1, b, N); 82 printf("%d\n", min(ans, ans2)); 83 } 84 return 0; 85 }
pat 1046 Shortest Distance(20 分) (线段树)
标签:stdin can scan text car tor htm ups Fix
原文地址:https://www.cnblogs.com/GetcharZp/p/9589797.html