leetcode 60-80 easy

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66、Plus One

Given a non-empty array of digits representing a non-negative integer, plus one to the integer.

The digits are stored such that the most significant digit is at the head of the list, and each element in the array contain a single digit.

You may assume the integer does not contain any leading zero, except the number 0 itself.

Example 1:

Input: [1,2,3]
Output: [1,2,4]
Explanation: The array represents the integer 123.

Example 2:

Input: [4,3,2,1]
Output: [4,3,2,2]
Explanation: The array represents the integer 4321.

C++

class Solution {
public:
    vector<int> plusOne(vector<int> &digits) {
        bool carry = true;
        
        for(int i=digits.size()-1; i >= 0 && carry; i--) {
            carry = (++digits[i]%=10) == 0;
        }

        if(carry) {
            digits.insert(digits.begin(), 1);
        }
    
        return digits;
    }
};

67. Add Binary

Given two binary strings, return their sum (also a binary string).

The input strings are both non-empty and contains only characters 1 or 0.

Example 1:

Input: a = "11", b = "1"
Output: "100"

Example 2:

Input: a = "1010", b = "1011"
Output: "10101"

C++

class Solution {
public:
    string addBinary(string a, string b) {
         string s = "";
        
        int c = 0, i = a.size() - 1, j = b.size() - 1;
        while(i >= 0 || j >= 0 || c == 1)
        {
            c += i >= 0 ? a[i --] - ‘0‘ : 0;
            c += j >= 0 ? b[j --] - ‘0‘ : 0;
            s = char(c % 2 + ‘0‘) + s;
            c /= 2;
        }
        
        return s;
    }
};

leetcode 60-80 easy

标签：out   return   int   bin   its   span   ica   pre   sig   

原文地址：https://www.cnblogs.com/hotsnow/p/9595630.html