二进制中1的个数

# -*- coding:utf-8 -*-
class Solution:
    def NumberOf1(self, n):
        # write code here
        return sum([(n>>i & 1) for i in range(0,32)])

# -*- coding:utf-8 -*-
class Solution:
    def NumberOf1(self, n):
        # write code here
        count = 0
        while n:
            count += 1
            n = (n-1) & n
        return count