ccf 水题集

#include<iostream>
using namespace std;
int main()
{
    int n;
    cin >> n;
    for(int i=1;i<=1000;i++)
    {
        int T=i*100;
        int cnt=T-3500;
        int fei=0;
        int ans=T-n;
        if(cnt<=0&&T==n)
        {
            cout << T << endl;
            break;
        }
        if(cnt<=0)
            continue;

        if(cnt<=1500)
        {
            fei+=cnt*0.03;
            if(fei==ans)
            {
                cout << T << endl;
                break;
            }
            continue;
        }
        if(cnt<=4500)
        {
            fei+=1500*0.03+(cnt-1500)*0.1;
            if(fei==ans)
            {
                cout << T << endl;
                break;
            }
            continue;
        }

        if(cnt<=9000)
        {
            fei+=1500*0.03+3000*0.1+(cnt-4500)*0.2;
            if(fei==ans)
            {
                cout << T <<endl;
                break;
            }
            continue;
        }
         if(cnt<=35000)
        {
            fei+=1500*0.03+3000*0.1+4500*0.2+(cnt-9000)*0.25;

            if(fei==ans)
            {
                cout << T << endl;
                break;
            }
            continue;
        }
         if(cnt<=55000)
        {
            fei+=1500*0.03+3000*0.1+4500*0.2+26000*0.25+(cnt-35000)*0.3;
            if(fei==ans)
            {
                cout << T << endl;
                break;
            }
            continue;
        }
         if(cnt<=80000)
        {
            fei+=1500*0.03+3000*0.1+4500*0.2+26000*0.25+20000*0.3+(cnt-55000)*0.35;
            if(fei==ans)
            {
                cout <<T <<endl;
                break;
            }
            continue;
        }
        if(cnt>80000)
        {
            fei+=1500*0.03+3000*0.1+4500*0.2+26000*0.25+20000*0.3+25000*0.35+(cnt-80000)*0.45;
            if(fei==ans)
            {
                cout << T << endl;
                break;
            }
            continue;
        }
    }
    return 0;
}