标签：style blog color io ar java for strong sp
Implement regular expression matching with support for ‘.‘ and
‘*‘.
‘.‘ Matches any single character.
‘*‘ Matches zero or more of the preceding element.
The matching should cover the entire input string (not partial).
The function prototype should be:
bool isMatch(const char *s, const char *p)
Some examples:
isMatch("aa","a") → false
isMatch("aa","aa") → true
isMatch("aaa","aa") → false
isMatch("aa", "a*") → true
isMatch("aa", ".*") → true
isMatch("ab", ".*") → true
isMatch("aab", "c*a*b") → true
public class Solution {
public boolean match(char s,char p)
{
return s==p||p=='.';
}
public boolean isMatch(String s, String p)
{
int sLen = s.length();
int pLen = p.length();
int i;
int j;
int k;
boolean[][] match = new boolean[sLen+1][pLen+1];
match[0][0]=true;
for(i=0;i<sLen;i++)
{
match[i+1][0]=false;
}
for(j=0;j<pLen;j++)
{
if(p.charAt(j)=='*')
{
match[0][j+1]=match[0][j-1];
}
else
{
match[0][j+1]=false;
}
}
for (i = 0; i < sLen; i++ )
{
for (j = 0; j < pLen; j++ )
{
if (p.charAt(j) == '*')
{
//0个、1个或多个
match[i+1][j+1]=match[i+1][j-1]||match[i+1][j]||(match(s.charAt(i),p.charAt(j-1))&&match[i][j+1]);
}
else
{
match[i+1][j+1]=match(s.charAt(i),p.charAt(j))&&match[i][j];
}
}
}
return match[sLen ][pLen ];
}
}标签：style blog color io ar java for strong sp
原文地址：http://blog.csdn.net/jiewuyou/article/details/39894917
