标签:swap void long begin bool mdf printf const vector
https://www.luogu.org/problemnew/show/P2664
考虑对于每种颜色包含的点和这些点的子节点建出虚树,发现只要将一个联通块中的东西 Dp + 查分一下就行了
当然要考虑哪些东西要被加进去
如果把不是一个颜色的联通块放在一起加,里面就要算上 n - 联通块大小的贡献(画个图就行了
然后输出的时候每个点的贡献要 + n (因为自己对任何一个点的连边肯定包含自己这种颜色
#include <bits/stdc++.h>
#define int long long
using namespace std;
const int N = 2e5 + 5, LG = 18;
vector <int> col[N], G[N], mdf[N], G2[N];
int pre[N][LG + 1], dep[N], sta[N], a[N], s[N], id[N], siz[N], book[N], f[N], h[N * 2];
int n, len, dfn, maxn, k;
void init(int u, int fa) {
pre[u][0] = fa; dep[u] = dep[fa] + 1; id[u] = ++dfn; siz[u] = 1;
for(int i = 1; i <= LG; i++) pre[u][i] = pre[pre[u][i - 1]][i - 1];
for(vector <int> :: iterator it = G[u].begin(); it != G[u].end(); it++)
if(*it != fa) init(*it, u), siz[u] += siz[*it];
}
int jump(int x, int k) {
for(int i = LG; i >= 0; i--)
if(k & (1 << i))
x = pre[x][i];
return x;
}
int LCA(int x, int y) {
if(dep[x] > dep[y]) swap(x, y);
y = jump(y, dep[y] - dep[x]);
if(x == y) return x;
for(int i = LG; i >= 0; i--)
if(pre[x][i] != pre[y][i])
x = pre[x][i], y = pre[y][i];
return pre[x][0];
}
bool cmp(int x, int y) {return id[x] < id[y];}
void dfs1(int u, int top) {
if(book[u] == 0 && G[u].size() == 0) {
f[u] = siz[u]; return;
}
if(book[u] == 1) {
f[u] = 0;
for(vector <int> :: iterator it = G[u].begin(); it != G[u].end(); it++) {
int len = (dep[*it] - dep[u] - 1);
int son = jump(*it, len);
if(book[*it] == 1) {
dfs1(*it, top);
int sz = siz[son] - siz[*it];
s[son] += (n - sz); s[*it] -= (n - sz);
} else {
mdf[son].clear(); dfs1(*it, son);
int sz = siz[son] - siz[*it];
int allsz = sz + f[*it];
s[son] += (n - allsz);
for(vector <int> :: iterator itt = mdf[son].begin(); itt != mdf[son].end(); itt++) s[*itt] -= (n - allsz);
}
}
} else {
f[u] = siz[u];
for(vector <int> :: iterator it = G[u].begin(); it != G[u].end(); it++) {
int len = (dep[*it] - dep[u] - 1);
int son = jump(*it, len);
dfs1(*it, top);
if(book[*it] == 1) {
mdf[top].push_back(*it);
f[u] -= siz[*it];
} else {
f[u] -= (siz[*it] - f[*it]);
}
}
}
}
void dfs2(int u, int fa) {
s[u] += s[fa];
for(vector <int> :: iterator it = G2[u].begin(); it != G2[u].end(); it++) {
if(*it != fa) dfs2(*it, u);
}
}
signed main() {
cin >> n;
for(int i = 1; i <= n; i++) {
scanf("%lld", &a[i]);
col[a[i]].push_back(i);
maxn = max(maxn, a[i]);
}
for(int i = 1; i < n; i++) {
int a, b;
scanf("%lld %lld", &a, &b);
G[a].push_back(b);
G[b].push_back(a);
G2[a].push_back(b);
G2[b].push_back(a);
}
init(1, 0);
G[n + 1].push_back(1); book[n + 1] = 1;
for(int i = 1; i <= maxn; i++) {
k = col[i].size();
for(int j = 0; j < k; j++) h[j + 1] = col[i][j], book[col[i][j]] = 1;
int tmp = k; bool have = 0;
for(int j = 1; j <= tmp; j++) {
int u = h[j];
if(u == 1) have = 1;
for(vector <int> :: iterator it = G2[u].begin(); it != G2[u].end(); it++) {
if(*it != pre[u][0]) h[++k] = *it;
}
}
if(!have) {
for(vector <int> :: iterator it = G2[1].begin(); it != G2[1].end(); it++) {
h[++k] = *it;
}
}
sort(h + 1, h + k + 1, cmp);
k = unique(h + 1, h + k + 1) - h - 1;
sort(h + 1, h + k + 1, cmp);
sta[len = 1] = 1; G[1].clear();
for(int j = 1; j <= k; j++) {
if(h[j] == 1) continue;
int lca = LCA(h[j], sta[len]);
if(lca != sta[len]) {
while(id[lca] < id[sta[len - 1]]) {
G[sta[len - 1]].push_back(sta[len]);
len--;
}
if(id[lca] > id[sta[len - 1]]) {
G[lca].clear();
G[lca].push_back(sta[len]);
sta[len] = lca;
} else G[lca].push_back(sta[len]), len--;
}
G[h[j]].clear(); sta[++len] = h[j];
}
for(int j = 1; j < len; j++) G[sta[j]].push_back(sta[j + 1]);
dfs1(n + 1, 0); for(int j = 0; j < tmp; j++) book[col[i][j]] = 0;
}
dfs2(1, 0);
for(int i = 1; i <= n; i++) printf("%lld\n", s[i] + n);
return 0;
}
标签:swap void long begin bool mdf printf const vector
原文地址:https://www.cnblogs.com/LJC00118/p/9636233.html