标签:unique public res int pat return obs row uniq
1 class Solution { 2 public int uniquePathsWithObstacles(int[][] obstacleGrid) { 3 if(obstacleGrid == null) return 0; 4 int row = obstacleGrid.length; 5 int col = obstacleGrid[0].length; 6 int[][] res = new int[row][col]; 7 if(obstacleGrid[0][0] != 1) { 8 res[0][0] = 1; 9 } 10 11 for(int i = 0; i < row; i++) { 12 for(int j = 0; j < col; j++) { 13 if(i == 0 && j == 0) continue; 14 if(obstacleGrid[i][j] != 1) { 15 if(i-1 < 0) { 16 res[i][j] = res[i][j-1]; 17 }else if(j-1 < 0) { 18 res[i][j] = res[i-1][j]; 19 }else { 20 res[i][j] = res[i][j-1] + res[i-1][j]; 21 } 22 }else { 23 continue; 24 } 25 } 26 } 27 return res[row-1][col-1]; 28 29 } 30 }
标签:unique public res int pat return obs row uniq
原文地址:https://www.cnblogs.com/goPanama/p/9644563.html