标签：att get ber pop front col gif push size
#include <bits/stdc++.h> using namespace std; const int MM = 1e5+5; const int INF = 1e9+7; int dis[MM]; int n, m; int s, t, k; int x, len, cnt[MM]; struct node{ int v, dis; }; vector <node> MMap[MM]; vector <node> reMMap[MM]; queue <int> q; int T; int a, b, l; node p; struct Edge{ int v, w; friend bool operator < (Edge a, Edge b){ return (a.w + dis[a.v]) > (b.w + dis[b.v]); } }; void spfa(int s) { bool vis[MM]; memset(vis, 0, sizeof(vis)); for (int i = 0; i < MM; ++i) dis[i] = INF; dis[s] = 0; vis[s] = true; while(!q.empty()) q.pop(); q.push(s); while (!q.empty()){ int u = q.front(); q.pop(); vis[u] = false; for (int i = 0; i < reMMap[u].size(); ++i){ int v = reMMap[u][i].v,w = reMMap[u][i].dis; if (dis[v] > dis[u] + w){ dis[v] = dis[u] + w; if (!vis[v]){ q.push(v); vis[v] = true; } } } } } int a_star(int s,int t){ Edge node1, node2; if (s == t) k++; if (dis[s] == INF) return -1; priority_queue <Edge> q; memset(cnt, 0, sizeof(cnt)); node1.w = 0,node1.v = s; q.push(node1); while (!q.empty()){ node2 = q.top(); q.pop(); len = node2.w; x = node2.v,cnt[x]++; if (cnt[t] == k) return len; if (cnt[x] > k) continue; int siz = MMap[node2.v].size(); for (int i = 0; i < siz; ++i) { node1.v = MMap[node2.v][i].v; node1.w = len + MMap[node2.v][i].dis; q.push(node1); } } return -1; } int main(){ while (~scanf("%d%d", &n, &m)){ scanf("%d%d%d%d", &s, &t, &k,&T); for (int i = 0; i < MM; ++i) MMap[i].clear(); for (int i = 0; i < MM; ++i) reMMap[i].clear(); for (int i = 1; i <= m; ++i){ scanf("%d%d%d", &a, &b, &l); p.v = b; p.dis = l; MMap[a].push_back(p); p.v = a; reMMap[b].push_back(p); } spfa(t); int tmp = a_star(s,t); if (tmp == -1) { puts("Whitesnake!");continue; } if (a_star(s,t) <= T) puts("yareyaredawa"); else puts("Whitesnake!"); } }
#include <bits/stdc++.h> using namespace std; typedef long long ll; const int maxn = 2005; int M[maxn][maxn]; int tx[maxn],ty[maxn]; int n,m,k,l,r,u,v; int main() { int cas = 1; while(~scanf("%d%d%d",&n,&m,&k)) { memset(M,0,sizeof(M)); scanf("%d%d",&l,&r); for(int i=0;i<k;i++) { scanf("%d%d",&u,&v); M[u][v]++; } int f = 1; for(int i=1;i<=n;i++){ int temp = 0; for(int j=1;j<=m;j++){ temp += M[i][j]; } tx[i] = temp; if(temp<l)f=0; } for(int i=1;i<=m;i++){ int temp = 0; for(int j=1;j<=n;j++){ temp += M[j][i]; } ty[i] = temp; if(temp<l)f=0; } if(f==0){ printf("Case %d: No\n",cas++);continue; } for(int i=1;i<=n;i++) { if(tx[i] > r) { int tt = tx[i] - r; for(int j=1;j<=m;j++){ int mi = min(tt,min(M[i][j],ty[j]-r)); tt -= mi;M[i][j] -= mi;ty[j] -= mi; if(tt == 0)break; } if(tt > 0){ for(int j=1;j<=m;j++){ int mi = min(tt,min(M[i][j],ty[j]-l)); tt -= mi;M[i][j] -= mi;ty[j] -= mi; if(tt == 0)break; } } if(tt > 0){ f = 0;break; } } } if(f){ printf("Case %d: Yes\n",cas++); } else{ printf("Case %d: No\n",cas++); } } return 0; }
#include <bits/stdc++.h> using namespace std; #define N 100000005 long long inv6 = 166666668; long long inv2 = 500000004; long long mod = 1e9+7; int p[20]; int main() { int n,m; while(~scanf("%d%d",&n,&m)){ int cnt = 0; for(int i = 2;i*i <= m;++i){ if(m % i == 0){ p[cnt++] = i; while(m%i == 0) m /= i; } } if(m != 1) p[cnt++] = m; int up = (1<<cnt); long long ans = 0; for(int i = 0;i < up;++i){ int tmp = 1; int kk = 0; for(int j = 0;j < cnt;++j){ if((i>>j)&1) kk++,tmp *= p[j]; } long long num = n/tmp; long long now = 1LL*tmp*tmp%mod*(num*2+1)%mod*(num+1)%mod*num%mod*inv6%mod; now = (now + 1LL* tmp * (1+num) % mod * num % mod * inv2 % mod) % mod; ans = (ans + now*(kk&1 ? -1 : 1) + mod) % mod; } printf("%lld\n",ans); } return 0; }
I Lattice‘s basics in digital electronics
#include <bits/stdc++.h> using namespace std; char s[20]; int mp[60000]; char str[200005]; bool code[1000006],nxt[1000005]; int main() { int T; cin >> T; while(T--){ memset(mp,0,sizeof(mp)); int m,n; scanf("%d%d",&m,&n); int v; for(int i = 1;i <= n;++i){ scanf("%d%s",&v,s); int len = strlen(s); int tmp = 0; for(int j = 0;j < len;++j){ tmp *= 3; tmp += s[j]-‘0‘+1; } mp[tmp] = v; } scanf("%s",str); int len = strlen(str); int now = 0; for(int i = 0;i < len;++i){ now += 4; int kk; if(str[i] >= ‘0‘ && str[i] <= ‘9‘) kk = str[i] - ‘0‘; else kk = str[i] - ‘a‘ + 10; for(int j = 1;j <= 4;++j){ code[now-j] = (kk & 1); kk >>= 1; } } int cnt; int tot = 0; for(int i = 0;i <= now;i+=9){ cnt = 0; for(int j = i;j < i+8;++j){ if(code[j]) cnt++; } if(((cnt&1) && code[i+8] == 0) || ((cnt&1) == 0 && code[i+8])){ for(int j = i;j < i+8;++j){ nxt[tot++] = code[j]; } } } int tmp = 0; cnt = 0; for(int i = 0;i < tot;++i){ if(cnt == m) break; tmp *= 3; tmp += nxt[i]+1; if(mp[tmp]){ cnt++; printf("%c",mp[tmp]); tmp = 0; } } puts(""); } return 0; }
#include <bits/stdc++.h> using namespace std; int ans[20] = {1,2,3,5,7,11,13,17,23,31,37,53,71,73,113,131,137,173,311,317}; char s[1005]; int main() { int T; cin >> T; cin.ignore(); int ii = 1; while(T--){ printf("Case #%d: ",ii++); gets(s); int len = strlen(s); if(len >= 4) puts("317"); else{ int tmp = 0; for(int i = 0;i < len;++i){ tmp *= 10; tmp += s[i]-‘0‘; } for(int i = 19;i >= 0;--i){ if(ans[i] <= tmp){ printf("%d\n",ans[i]); break; } } } } return 0; }
标签：att get ber pop front col gif push size
原文地址：https://www.cnblogs.com/solvit/p/9651794.html
