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关于反常积分收敛的专题讨论

时间:2014-05-14 09:49:48      阅读:341      评论:0      收藏:0      [点我收藏+]

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$\bf命题:$设$\int_a^{ + \infty } {f\left( x \right)dx} $收敛,若$\lim \limits_{x \to \begin{array}{*{20}{c}} {{\rm{ + }}\infty } \end{array}

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} f\left( x \right)$存在,则$\lim \limits_{x \to \begin{array}{*{20}{c}} {{\rm{ + }}\infty } \end{array}
} f\left( x \right) = 0$

参考答案

$\bf命题:$设$f\left( x \right) \in {C^1}\left[ {a, + \infty } \right)$,若$\int_a^{ + \infty } {f\left( x \right)dx} ,\int_a^{ + \infty } {f‘\left( x \right)dx}$均收敛,则$\lim \limits_{x \to \begin{array}{*{20}{c}}{ + \infty }\end{array}

} f\left( x \right) = 0$

参考答案

$\bf命题:$设${f\left( x \right)}$在$\left[ {a,{\rm{ + }}\infty } \right)$单调,且$\int_a^{ + \infty } {f\left( x \right)dx} $收敛,则$\lim \limits_{x \to \begin{array}{*{20}{c}}{ + \infty }\end{array}

} xf\left( x \right) = 0$,进而$\lim \limits_{x \to \begin{array}{*{20}{c}}{ + \infty }\end{array}
} f\left( x \right) = 0$

参考答案

$\bf命题:$设${f\left( x \right)}$在$\left[ {a, + \infty } \right)$上可微且单调下降,若$\int_a^{ + \infty } {f\left( x \right)dx} $收敛,则$\int_a^{ + \infty } {xf‘\left( x \right)dx} $收敛

参考答案

$\bf命题:$设$\int_a^{ + \infty } {f\left( x \right)dx} $收敛,且$\frac{{f\left( x \right)}}{x}$在${\left[ {a, + \infty } \right)}$上单调递减,则$\lim \limits_{x \to \begin{array}{*{20}{c}} { + \infty } \end{array}

} xf\left( x \right) = 0$

参考答案

$\bf命题:$设$f\left( x \right)$单调且$\lim \limits_{x \to \begin{array}{*{20}{c}} {{0^ + }} \end{array}

} f\left( x \right) = + \infty $,若$\int_0^1 {f\left( x \right)dx} $收敛,则$\lim \limits_{x \to \begin{array}{*{20}{c}} {{0^ + }} \end{array}
} xf\left( x \right) = 0$

参考答案

$\bf命题:$设$xf\left( x \right)$在${\left[ {a, + \infty } \right)}$上单调递减,若$\int_a^{ + \infty } {f\left( x \right)dx} $收敛,则$\lim \limits_{x \to \begin{array}{*{20}{c}} { + \infty } \end{array}

} xf\left( x \right)\ln x = 0$

参考答案

$\bf命题:$设$f\left( x \right)$在${\left[ {a, + \infty } \right)}$上一致连续,若$\int_a^{ + \infty } {f\left( x \right)dx} $收敛,则$\lim \limits_{x \to \begin{array}{*{20}{c}}{ + \infty }\end{array}

} f\left( x \right) = 0$

方法一   方法二

$\bf命题:$设$f\left( x \right)$在${\left[ {a, + \infty } \right)}$上可导且导函数有界,若$\int_a^{ + \infty } {f\left( x \right)dx} $收敛,则$\lim \limits_{x \to \begin{array}{*{20}{c}} { + \infty } \end{array}

} f\left( x \right) = 0$

$\bf命题:$设$f\left( x \right)$在${\left[ {a, + \infty } \right)}$上可导且导函数有界,若$\int_a^{ + \infty } {f\left( x \right)dx} $绝对收敛,则$\lim \limits_{x \to \begin{array}{*{20}{c}} { + \infty } \end{array}

} f\left( x \right) = 0$

参考答案

$\bf命题:$设$f\left( x \right)$在${\left[ {a, + \infty } \right)}$上可导且导函数有界,若$ \int_a^{ + \infty } {{f^2}\left( x \right)dx} < + \infty $,则$\lim \limits_{x \to \begin{array}{*{20}{c}} { + \infty } \end{array}

} f\left( x \right) = 0$

$\bf命题:$设$p \ge 1,f\left( x \right) \in {C^1}\left( { - \infty , + \infty } \right)$,且\int_{ - \infty }^{ + \infty } {{{\left| {f\left( x \right)} \right|}^p}dx} < + \infty ,\int_{ - \infty }^{ + \infty } {{{\left| {f‘\left( x \right)} \right|}^p}dx} < + \infty


证明:$\lim \limits_{x \to \begin{array}{*{20}{c}}\infty \end{array}
} f\left( x \right) = 0$,且{\left| {f\left( x \right)} \right|^p} \le \frac{{p - 1}}{2}\int_{ - \infty }^{ + \infty } {{{\left| {f\left( t \right)} \right|}^p}dt} + \frac{1}{2}\int_{ - \infty }^{ + \infty } {{{\left| {f‘\left( t \right)} \right|}^p}dt}

参考答案

$\bf命题:$设$f\left( x \right) \in C\left[ {a, + \infty } \right)$,且$\int_a^{ + \infty } {f\left( x \right)dx} $收敛,则存在数列$\left\{ {{x_n}} \right\} \subset \left[ {a, + \infty } \right)$,使得\mathop {\lim }\limits_{n \to\infty } {x_n} = + \infty ,\mathop {\lim }\limits_{n \to \infty } f\left( {{x_n}} \right) = 0

参考答案

$\bf命题:$设$\int_a^{{\rm{ + }}\infty } {f\left( x \right)dx} $绝对收敛,且$\lim \limits_{x \to \begin{array}{*{20}{c}}{{\rm{ + }}\infty }\end{array}

} f\left( x \right) = 0$,则$\int_a^{{\rm{ + }}\infty } {{f^2}\left( x \right)dx} $收敛 

参考答案

$\bf命题:$设$f\left( x \right)$在$\left[ {0, + \infty } \right)$上可微,$f‘\left( x \right)$在$\left[ {0, + \infty } \right)$上单调递增且无上界,则$\int_0^{ + \infty } {\frac{1}{{1 + {f^2}\left( x \right)}}dx} $收敛

参考答案

$\bf命题:$设正值函数$f\left( x \right)$在$\left[ {1, + \infty } \right)$上二阶连续可微,且$\lim \limits_{x \to \begin{array}{*{20}{c}}{ + \infty }\end{array}

} f‘‘\left( x \right) = + \infty $,则$\int_1^{ + \infty } {\frac{1}{{f\left( x \right)}}dx} $收敛

参考答案

$\bf命题:$




 

 

 



 

关于反常积分收敛的专题讨论,布布扣,bubuko.com

关于反常积分收敛的专题讨论

标签:style   blog   class   c   ext   color   

原文地址:http://www.cnblogs.com/ly142857/p/3664523.html

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