标签:style blog color io os ar for sp div
You are given a grid of numbers. A snake sequence is made up of adjacent numbers such that for each number, the number on the right or the number below it is +1 or -1 its value.
For example
1 3 2 6 8
-9 7 1 -1 2
1 5 0 1 9
output : 3 2 1 0 1
1. Given a grid, find the longest snake sequences and their lengths (so there can be multiple snake sequences with the maximum length).
public class Solution { public List<List<Integer>> SnakeSequence(int[][] grid) { List<List<Integer>> ret = new LinkedList<List<Integer>>(); int m = grid.length; int n = grid[0].length; int[][] dp = new int[m][n]; int longest = 0; for(int i=0; i<m; i++) { for(int j=0; j<n; j++) { if(i>0 && Math.abs(grid[i-1][j]-grid[i][j])==1) { dp[i][j] = Math.max(dp[i][j], dp[i-1][j]+1); } if(j>0 && Math.abs(grid[i][j-1]-grid[i][j])==1) { dp[i][j] = Math.max(dp[i][j], dp[i][j-1]+1); } if(dp[i][j]>longest) { longest = dp[i][j]; } } } }
2. What about the longest increasing(by +1) snake sequence. This time, the numbers are in an increasing order in the sequence.
For example
2 3 4 5
4 5 10 11
20 6 9 12
6 7 8 40
output : 4 5 6 7 8 9 10 11 12
// // main.cpp // TestC_cpp // // Created by Joyce on 14-10-8. // Copyright (c) 2014年 Yang Li. All rights reserved. // #include <iostream> using namespace std; int arr[4][4] = {{2,3,4,5},{4,5,10,11},{20,6,9,12},{6,7,8,40}}; // given array. int temp[4][4]; int M=4, N=4; int fill(int temp[][4], int i, int j){ if(i<0 || j<0 || i>=M || j>=N) return 0; if(temp[i][j] != 0) return temp[i][j]; int left=0,right=0,up=0,down=0; if(arr[i-1][j] == arr[i][j] +1){ /// cpp compiler won‘t claim if the idx is over limit up = fill(temp,i-1,j); if(up+1>temp[i][j]) temp[i][j] = up+1; } if(arr[i+1][j] == arr[i][j] +1) { down = fill(temp,i+1,j); if(down+1>temp[i][j]) temp[i][j] = down+1; } if(arr[i][j-1] == arr[i][j] +1){ left = fill(temp,i,j-1); if(left+1>temp[i][j]) temp[i][j] = left+1; } if(arr[i][j+1] == arr[i][j] +1){ right = fill(temp,i,j+1); if(right+1>temp[i][j]) temp[i][j] = right+1; } return temp[i][j]; } int main(int arg, char** args) { int i, j; for (i=0;i<M;i++){ for(j=0;j<N;j++){ if(temp[i][j] == 0){ fill(temp,i,j); } } } for(i=0; i<4; i++) { for(j=0; j<4; j++) { cout<<temp[i][j]; } cout<<‘\n‘; } // find the max elem in temp int max_x=0, max_y=0; for(i=0;i<M;i++){ for(j=0;j<N;j++){ if(temp[i][j] > temp[max_x][max_y]){ max_x = i; max_y = j; } } } // find the path i=max_x, j= max_y ; cout<<arr[i][j]<<‘,‘; while(temp[i][j] != 0){ if(temp[i-1][j] == temp[i][j]-1 && arr[i-1][j] == arr[i][j]+1){ i = i-1; cout<<arr[i][j]<<‘,‘; continue; } if(temp[i+1][j] == temp[i][j]-1 && arr[i+1][j] == arr[i][j]+1){ i = i+1; cout<<arr[i][j]<<‘,‘; continue; } if(temp[i][j-1] == temp[i][j]-1 && arr[i][j-1] == arr[i][j]+1){ j = j-1; cout<<arr[i][j]<<‘,‘; continue; } if(temp[i][j+1] == temp[i][j]-1 && arr[i][j+1] == arr[i][j]+1){ j = j+1; cout<<arr[i][j]<<‘,‘; continue; } } }
标签:style blog color io os ar for sp div
原文地址:http://www.cnblogs.com/joycelee/p/4013062.html