标签:cst stream root next set 思路 eof ring str
链接:http://poj.org/problem?id=2114
题意:
求树上距离为k的点对数量;
思路:
点分治。。
实现代码:
#include<iostream> #include<cstdio> #include<cstring> #include<algorithm> using namespace std; #define ll long long #define inf 0x7fffffff const int M = 1e5+10; struct node{ int to,next,w; }e[M<<2]; int n,m; int vis[M],dis[M],d[M],siz[M],f[M],cnt,head[M],sum,root,k,ans; void init(){ cnt = 0; ans = 0; memset(head,0,sizeof(head)); memset(vis,0,sizeof(vis)); } void add(int u,int v,int w){ e[++cnt].to = v;e[cnt].w = w;e[cnt].next = head[u];head[u] = cnt; } void get_root(int u,int fa){ siz[u] = 1; f[u] = 0; for(int i = head[u];i;i=e[i].next){ int v = e[i].to; if(v != fa&&!vis[v]){ get_root(v,u); siz[u] += siz[v]; f[u] = max(f[u],siz[u]); } } f[u] = max(f[u],sum - siz[u]); if(f[u] < f[root]) root = u; return ; } void get_dis(int u,int fa){ if(d[u] <= k) dis[++dis[0]] = d[u]; for(int i = head[u];i;i=e[i].next){ int v = e[i].to; if(v != fa&&!vis[v]){ d[v] = d[u] + e[i].w; get_dis(v,u); } } return ; } int cal(int u,int c){ d[u] = c; dis[0] = 0; get_dis(u,0); sort(dis+1,dis+dis[0]+1); int l = 1,r = dis[0],ans = 0; while(l < r){ if(dis[l] + dis[r] < k) l++; else if(dis[l] + dis[r] > k) r--; else{ if(dis[l] == dis[r]){ ans += (r-l+1)*(r-l)/2; break; } else { int i = l,j = r; while(dis[i] == dis[l]) i++; while(dis[j] == dis[r]) j--; ans += (i-l)*(r-j); l = i; r = j; } } } return ans; } void solve(int u){ ans += cal(u,0); vis[u] = 1; for(int i = head[u];i;i=e[i].next){ int v = e[i].to; if(vis[v]) continue; ans -= cal(v,e[i].w); sum = siz[v]; root = 0; get_root(v,0); solve(root); } } int main() { int u,v,w; while(scanf("%d",&n)&&n){ init(); for(int i = 1;i <= n;i ++){ int x,v; while(scanf("%d",&x)&&x){ scanf("%d",&v); add(i,x,v); add(x,i,v); } } int x; while(scanf("%d",&x)&&x){ memset(vis,0,sizeof(vis)); k = x; ans = root = 0; sum = n; f[0] = inf; get_root(1,0); solve(root); if(ans) printf("AYE\n"); else printf("NAY\n"); } printf(".\n"); } }
标签:cst stream root next set 思路 eof ring str
原文地址:https://www.cnblogs.com/kls123/p/9729045.html