标签:define hdu sse tip problem output 递归 mem ros
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 43278 Accepted Submission(s): 9449
//第一版,直接暴力递归,超时 #include<iostream> using namespace std; long long int fac(int A, int B, int n) { if (n == 1 || n == 2) return 1; else return (A * fac(A,B,n - 1) + B * fac(A,B,n - 2)) % 7; } int main() { int A, B, n; while (cin >> A >> B >> n&&A != 0 && B != 0 && n != 0) { cout << fac(A, B, n % 48) << endl; } return 0; }
标签:define hdu sse tip problem output 递归 mem ros
原文地址:https://www.cnblogs.com/gcter/p/9738661.html