标签：des style blog http color io os ar for
Moon Game
Description
Fat brother and Maze are playing a kind of special (hentai) game in the clearly blue sky which we can just consider as a kind of two-dimensional plane. Then Fat brother starts to draw N starts in the sky which we can just consider each as a point. After he draws these stars, he starts to sing the famous song “The Moon Represents My Heart” to Maze.
You ask me how deeply I love you,
How much I love you?
My heart is true,
My love is true,
The moon represents my heart.
…
But
as Fat brother is a little bit stay-adorable(呆萌), he just consider that
the moon is a special kind of convex quadrilateral and starts to count
the number of different convex quadrilateral in the sky. As this number
is quiet large, he asks for your help.
Input
The first line of the date is an integer T, which is the number of the text cases.
Then T cases follow, each case contains an integer N describe the number of the points.
Then N lines follow, Each line contains two integers describe the coordinate of the point, you can assume that no two points lie in a same coordinate and no three points lie in a same line. The coordinate of the point is in the range[-10086,10086].
1 <= T <=100, 1 <= N <= 30
Output
For
each case, output the case number first, and then output the number of
different convex quadrilateral in the sky. Two convex quadrilaterals are
considered different if they lie in the different position in the sky.
Sample Input
Sample Output
1 #include <iostream> 2 #include <cstdio> 3 #include <cstdlib> 4 #include <cstring> 5 #include <cmath> 6 #include <algorithm> 7 #include <set> 8 #include <map> 9 #include <queue> 10 #include <string> 11 #include <vector> 12 #define inf 0x3fffffff 13 14 using namespace std; 15 16 struct point 17 { 18 int x, y; 19 }p[35]; 20 21 point a1, a2, a3, a4; 22 23 bool inter(point a, point b, point c, point d) 24 { 25 if( 26 min(a.x, b.x) > max(c.x, d.x) || 27 min(a.y, b.y) > max(c.y, d.y) || 28 min(c.x, d.x) > max(a.x, b.x) || 29 min(c.y, d.y) > max(a.y, b.y) 30 ) 31 return 0; 32 long long x1, x2, x3, x4; 33 x1 = (b.x - a.x) * (c.y - a.y) - (b.y - a.y) * (c.x - a.x); 34 x2 = (b.x - a.x) * (d.y - a.y) - (b.y - a.y) * (d.x - a.x); 35 x3 = (d.x - c.x) * (a.y - c.y) - (d.y - c.y) * (a.x - c.x); 36 x4 = (d.x - c.x) * (b.y - c.y) - (d.y - c.y) * (b.x - c.x); 37 return x1 * x2 < 0 && x3 * x4 < 0; 38 } 39 40 bool fun() 41 { 42 if (inter(a1, a2, a3, a4)) return 1; 43 if (inter(a1, a3, a2, a4)) return 1; 44 if (inter(a1, a4, a2, a3)) return 1; 45 return 0; 46 } 47 48 int main() 49 { 50 //freopen ("test.txt", "r", stdin); 51 int T; 52 scanf ("%d", &T); 53 for (int times = 1; times <= T; ++times) 54 { 55 int n; 56 scanf ("%d", &n); 57 for (int i = 0; i < n; ++i) 58 { 59 scanf ("%d%d", &p[i].x, &p[i].y); 60 } 61 int ans = 0; 62 for (int i = 0; i < n; ++i) 63 { 64 a1 = p[i]; 65 for (int j = i + 1; j < n; ++j) 66 { 67 a2 = p[j]; 68 for (int k = j + 1; k < n; ++k) 69 { 70 a3 = p[k]; 71 for (int h = k + 1; h < n; ++h) 72 { 73 a4 = p[h]; 74 if (fun()) ans++; 75 } 76 } 77 } 78 } 79 printf ("Case %d: %d\n", times, ans); 80 } 81 return 0; 82 }
ACM学习历程—FZU2148 Moon Game（计算几何）
标签：des style blog http color io os ar for
原文地址：http://www.cnblogs.com/andyqsmart/p/4014521.html
