标签：input orm esc 比赛 mon deb which mes gem
Zhenya moved from his parents’ home to study in other city. He didn’t take any cash with him, he only took his father’s credit card with zero balance on it. Zhenya succeeds in studies at the University and sometimes makes a little
money on the side as a Maths tutor. As he makes his own money he spends only it, and when it is over he uses the credit card. Every time he gets or spends money, he sends a letter to his father, where he puts the following two things.
The date when it took placeThe sum of earned or spent money
Every time receiving a letter from Zhenya, his father calculates the debt on the credit card at the moment. But here a problem arises. The point is that Russian Post delivers letters in an order different to the one they were
sent in.
For example, in the first Zhenya’s letter the father read that on September 10 Zhenya spent one thousand rubles. He thought that his son had used the credit card, and now the debt is one thousand rubles. However the next day
came a letter with the information that on September 9 Zhenya earned five hundred rubles. It means that half of the money he spent on September 10 was his own, and the debt on the credit card is just five hundred rubles.
Help Zhenya’s father with his account management.
The first line contains an integer n which is the number of Zhenya’s letters (1 ≤ n ≤ 100 000). These letters are listed in the next n lines. Description of each letter consists of the amount of money
Zhenya spent or earned (in the form -c or +c accordingly, where c is an integer, 1 ≤ c ≤ 50 000) followed by both date and time when it took place (in the form of dd.MM hh:mm). All dates belong to the same year, which is not leap (i. e. there are
365 days in it). Any two letters contain either different dates or different time. The letters are listed in the order the father received them.
After each received letter output what Zhenya’s father thinks the amount of the debt on the credit card is.
5
-1000 10.09 21:00
+500 09.09 14:00
+1000 02.09 00:00
-1000 17.09 21:00
+500 18.09 13:00
-1000
-500
0
-500
-500
对线段树离散化进一步掌握了，不亏
#include<bits/stdc++.h>
#define sf scanf
#define scf(x) scanf("%d",&x)
#define pf printf
#define rep(i,a,n) for (int i=a;i<n;i++)
#define per(i,a,n) for (int i=a;i>=n;i--)
#define mm(x,b) memset((x),(b),sizeof(x))
#define ls l,mid,i<<1
#define rs mid+1,r,i<<1|1
#define ll long long
using namespace std;
const int N=1e5+100;
struct tree
{
int l,r;
ll lazy,ans;
}tr[N<<4];
void built_tree(int l,int r,int i)
{
tr[i].l =l;tr[i].r =r;
tr[i].lazy =0;
if(l==r)
{
tr[i].ans=0;
return ;
}
int mid=(l+r)>>1;
built_tree(ls);
built_tree(rs);
tr[i].ans =min(tr[i<<1].ans ,tr[i<<1|1].ans);
}
void pushdown(int i)
{
if(tr[i].lazy)
{
tr[i<<1].lazy +=tr[i].lazy;
tr[i<<1|1].lazy +=tr[i].lazy;
tr[i<<1].ans +=tr[i].lazy;
tr[i<<1|1].ans +=tr[i].lazy;
tr[i].lazy =0;
}
}
void update(int l,int r,ll k,int i)
{
if(l<=tr[i].l&&tr[i].r<=r)
{
tr[i].ans +=k;
tr[i].lazy+=k;
return;
}
pushdown(i);
int mid=(tr[i].l+tr[i].r)>>1;
if(r<=mid)
update(l,r,k,i<<1);
else if(l>mid)
update(l,r,k,i<<1|1);
else
{
update(l,r,k,i<<1);
update(l,r,k,i<<1|1);
}
tr[i].ans=min(tr[i<<1].ans,tr[i<<1|1].ans);
}
ll query(int l,int r,int i)
{
if(tr[i].l ==l&&tr[i].r==r)
return tr[i].ans;
pushdown(i);
int mid=(tr[i].l+tr[i].r)>>1;
if(r<=mid)
return query(l,r,i<<1);
else if(l>mid)
return query(l,r,i<<1|1);
else return min(query(l,r,i<<1),query(l,r,i<<1|1));
}
int mon[13]={0,31,28,31,30,31,30,31,31,30,31,30,31};
struct Time
{
ll t,id,bits,k;
}T[N];
bool cmp1(Time a,Time b)
{
return a.t <b.t ;
}
bool cmp2(Time a,Time b)
{
return a.id <b.id ;
}
int main()
{
rep(i,1,13)
mon[i]+=mon[i-1];
int n;
ll k,d,m,s,f;
scf(n);
rep(i,0,n)
{
sf("%lld %lld.%lld %lld:%lld",&k,&d,&m,&s,&f);
ll bit=(mon[m-1]+d)*24*60+s*60+f;
T[i].t=bit;
T[i].id =i;
T[i].k =k;
}
built_tree(0,n,1);
sort(T,T+n,cmp1);
rep(i,0,n)
T[i].bits =i;
sort(T,T+n,cmp2);
rep(i,0,n)
{
update(T[i].bits ,n,T[i].k ,1);
ll ans=tr[1].ans;
if(ans>=0)
pf("0\n");
else pf("%lld\n",ans);
}
return 0;
}
标签：input orm esc 比赛 mon deb which mes gem
原文地址：https://www.cnblogs.com/wzl19981116/p/9757089.html
