标签:call led info ack overflow sch val 获取 warning
上篇中已经分析了DAGscheduler的监听机制,以及job的划分,这次我们再来看一看stage是如何划分以及stage的最终提交;
当jobsubmit 加入到DAGscheduler的event队列中的时候,
就会将job的stage划分为resultstage 和 shufflestage,其中一个job只会有一个resultstage;
stage的划分上,首先从最后一个stage开始,最先创建一个resultstage,然后依次向前递归实现stage的划分。
private[scheduler] def handleJobSubmitted(jobId: Int, finalRDD: RDD[_], func: (TaskContext, Iterator[_]) => _, partitions: Array[Int], callSite: CallSite, listener: JobListener, properties: Properties) { var finalStage: ResultStage = null try { // New stage creation may throw an exception if, for example, jobs are run on a // HadoopRDD whose underlying HDFS files have been deleted. // Stage划分过程是从最后一个Stage开始往前执行的,最后一个Stage的类型是ResultStage finalStage = newResultStage(finalRDD, func, partitions, jobId, callSite) } catch { case e: Exception => logWarning("Creating new stage failed due to exception - job: " + jobId, e) listener.jobFailed(e) return } //为该Job生成一个ActiveJob对象,并准备计算这个finalStage val job = new ActiveJob(jobId, finalStage, callSite, listener, properties) clearCacheLocs() logInfo("Got job %s (%s) with %d output partitions".format( job.jobId, callSite.shortForm, partitions.length)) logInfo("Final stage: " + finalStage + " (" + finalStage.name + ")") logInfo("Parents of final stage: " + finalStage.parents) logInfo("Missing parents: " + getMissingParentStages(finalStage)) val jobSubmissionTime = clock.getTimeMillis() jobIdToActiveJob(jobId) = job // 该job进入active状态 activeJobs += job finalStage.setActiveJob(job) val stageIds = jobIdToStageIds(jobId).toArray val stageInfos = stageIds.flatMap(id => stageIdToStage.get(id).map(_.latestInfo)) listenerBus.post( // 向LiveListenerBus发送Job提交事件 SparkListenerJobStart(job.jobId, jobSubmissionTime, stageInfos, properties)) submitStage(finalStage) //提交当前Stage submitWaitingStages() }
在划分中,根据创建的resultstage,去获取result的parentstage进行递归调用;
private def newResultStage( rdd: RDD[_], func: (TaskContext, Iterator[_]) => _, partitions: Array[Int], jobId: Int, callSite: CallSite): ResultStage = { // 获取当前Stage的parent Stage,这个方法是划分Stage的核心实现 (递归调用实现) val (parentStages: List[Stage], id: Int) = getParentStagesAndId(rdd, jobId) val stage = new ResultStage(id, rdd, func, partitions, parentStages, jobId, callSite)// 创建当前最后的ResultStage stageIdToStage(id) = stage // 将ResultStage与stageId相关联 updateJobIdStageIdMaps(jobId, stage) // 更新该job中包含的stage stage }
递归调用的终点,获取parentstage 和 stageid 的结果返回,由于这个是由后向前的递归调用(使用广度优先策略),那么最先执行的stageid 则是最小的0
private def getParentStagesAndId(rdd: RDD[_], firstJobId: Int): (List[Stage], Int) = { val parentStages = getParentStages(rdd, firstJobId) // 传入rdd和jobId,生成parentStage // 生成当前stage的stageId。同一Application中Stage初始编号为0 val id = nextStageId.getAndIncrement() (parentStages, id) }
private def getParentStages(rdd: RDD[_], firstJobId: Int): List[Stage] = { val parents = new HashSet[Stage] // 存储当前stage的所有parent stage val visited = new HashSet[RDD[_]] // 存储访问过的rdd // We are manually maintaining a stack here to prevent StackOverflowError // caused by recursively visiting val waitingForVisit = new Stack[RDD[_]] // 一个栈,保存未访问过的rdd,先进后出 def visit(r: RDD[_]) { if (!visited(r)) { // 如果栈中弹出的rdd被未访问过 visited += r // 首先将其标记为已访问 // Kind of ugly: need to register RDDs with the cache here since // we can‘t do it in its constructor because # of partitions is unknown for (dep <- r.dependencies) { // 读取当然rdd的依赖 dep match { case shufDep: ShuffleDependency[_, _, _] => // 如果是宽依赖,则获取依赖rdd所在的ShuffleMapStage parents += getShuffleMapStage(shufDep, firstJobId) case _ => // 如果是窄依赖,将依赖的rdd也压入栈中,下次循环时会探索该rdd的依赖情况,直到找到款依赖划分新的stage为止 waitingForVisit.push(dep.rdd) } } } } waitingForVisit.push(rdd) // 将当前rdd压入栈中 while (waitingForVisit.nonEmpty) { // 如果栈中有未被访问的rdd visit(waitingForVisit.pop()) // } parents.toList }
参考资料:https://blog.csdn.net/dabokele/article/details/51902617
标签:call led info ack overflow sch val 获取 warning
原文地址:https://www.cnblogs.com/yankang/p/9771778.html