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559. Maximum Depth of N-ary Tree

时间:2018-10-14 20:53:01      阅读:102      评论:0      收藏:0      [点我收藏+]

标签:bsp   cout   long   down   col   def   des   The   src   

Given a n-ary tree, find its maximum depth.

The maximum depth is the number of nodes along the longest path from the root node down to the farthest leaf node.

For example, given a 3-ary tree:

 

技术分享图片

 

We should return its max depth, which is 3.

 

Note:

  1. The depth of the tree is at most 1000.
  2. The total number of nodes is at most 5000.
#include<vector>
#include <cstdlib>
#include<iostream>

using namespace std;

// Definition for a Node.
class Node {
public:
    int val;
    vector<Node *> children;

    Node() {}

    Node(int _val, vector<Node *> _children) {
        val = _val;
        children = _children;
    }
};

class Solution {
public:
    int maxDepth(Node *root) {
        if (root == NULL)
            return 0;
        int res = 1;
        for (int i = 0; i < root->children.size(); ++i) {
            res = max(res, 1 + maxDepth(root->children[i]));
        }
        return res;
    }
};

int main() {
    Node *node5 = new Node(5, {});
    Node *node6 = new Node(6, {});
    Node *node3 = new Node(3, {node5, node6});
    Node *node2 = new Node(2, {});
    Node *node4 = new Node(4, {});
    Node *node1 = new Node(1, {node3, node2, node4});
    Solution solution;
    int res = solution.maxDepth(node1);
    std::cout << "res: " << res << endl;
    return 0;
}

 

559. Maximum Depth of N-ary Tree

标签:bsp   cout   long   down   col   def   des   The   src   

原文地址:https://www.cnblogs.com/learning-c/p/9787472.html

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