标签:bsp cout long down col def des The src
Given a n-ary tree, find its maximum depth.
The maximum depth is the number of nodes along the longest path from the root node down to the farthest leaf node.
For example, given a 3-ary
tree:
We should return its max depth, which is 3.
Note:
1000
.5000
.#include<vector> #include <cstdlib> #include<iostream> using namespace std; // Definition for a Node. class Node { public: int val; vector<Node *> children; Node() {} Node(int _val, vector<Node *> _children) { val = _val; children = _children; } }; class Solution { public: int maxDepth(Node *root) { if (root == NULL) return 0; int res = 1; for (int i = 0; i < root->children.size(); ++i) { res = max(res, 1 + maxDepth(root->children[i])); } return res; } }; int main() { Node *node5 = new Node(5, {}); Node *node6 = new Node(6, {}); Node *node3 = new Node(3, {node5, node6}); Node *node2 = new Node(2, {}); Node *node4 = new Node(4, {}); Node *node1 = new Node(1, {node3, node2, node4}); Solution solution; int res = solution.maxDepth(node1); std::cout << "res: " << res << endl; return 0; }
559. Maximum Depth of N-ary Tree
标签:bsp cout long down col def des The src
原文地址:https://www.cnblogs.com/learning-c/p/9787472.html