LeetCode 58. Length of Last Word

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分析

难度 易

来源

https://leetcode.com/problems/length-of-last-word/description/

题目

Given a string s consists of upper/lower-case alphabets and empty space characters ‘ ‘, return the length of last word in the string.

If the last word does not exist, return 0.

Note: A word is defined as a character sequence consists of non-space characters only.

Example:

Input: "Hello World"

Output: 5

解答

 1 package LeetCode;
 2 
 3 public class L58_LengthOfLastWord {
 4     public int lengthOfLastWord(String s) {
 5         String[] strs;
 6         strs=s.split(" ");
 7         if(strs.length==0)
 8             return 0;
 9         else
10             return strs[strs.length-1].length();
11     }
12 }

LeetCode 58. Length of Last Word

标签：cte   ase   ast   define   and   lse   turn   ems   ali   

原文地址：https://www.cnblogs.com/flowingfog/p/9808407.html