测试数学工具编辑

标签：class   keyword   key   span   number   工具   bre   ali   sum   

$$sum=\sum_{i=0}^{n}w_i(y_i-\breve{y})$$

$$ \begin{align} \frac{\partial J(\theta)}{\partial\theta_j} & = -\frac1m\sum_{i=0}^m(y^i-h_\theta(x^i)) \frac{\partial}{\partial\theta_j}(y^i-h_\theta(x^i)) \\ & = -\frac1m\sum_{i=0}^m(y^i-h_\theta(x^i)) \frac{\partial}{\partial\theta_j}(\sum_{j=0}^n\theta_jx_j^i-y^i) \\ & = -\frac1m\sum_{i=0}^m(y^i-h_\theta(x^i))x^i_j \end{align} $$

测试数学工具编辑

标签：class   keyword   key   span   number   工具   bre   ali   sum   

原文地址：https://www.cnblogs.com/kangxinxin/p/9815721.html